cutting a matrix A into 3 pieces with respect to matrix B
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Mori
am 17 Jul. 2015
Bearbeitet: Mori
am 17 Jul. 2015
here we have :
A=[1 2 3 14 15 16 7 8]
B=[1 2 3]
we know location of B is over 14 15 16 of matrix A.
we need to get 3 different matrix as below:
c=[1 2 3]
d=[14 15 16]
e=[7 8]
whar are the commands? many thanks in advance
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Walter Roberson
am 17 Jul. 2015
Is it known that those entries in B are bit-for-bit copies of the entries in A? Such as if A was indexed to produce B? Because when two floating point values are computed by even very very slightly different code, the results will not necessarily be equal due to floating point round-off. If the entries are not bit-for-bit copies then you will need to compare with a tolerance rather than compare for equality.
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Walter Roberson
am 17 Jul. 2015
[tf, idx] = ismember(B, A, 'rows');
minidx = min(idx);
maxidx = max(idx);
c = A(1:minidx-1,:);
d = A(minidx:maxidx,:);
e = A(maxidx+1:end, :);
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