Can someone assist please:

1 Kommentar

Azzi Abdelmalek
Azzi Abdelmalek am 14 Jul. 2015
Bearbeitet: Azzi Abdelmalek am 14 Jul. 2015
Do you mean for the first week of each month or of what? can you give more details about your first column?

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

Andrei Bobrov
Andrei Bobrov am 14 Jul. 2015
Bearbeitet: Andrei Bobrov am 15 Jul. 2015

1 Stimme

% data - your data; first column - data+time, second - Power
data = [timeprac1,P];
v = datevec(data(:,1));
a = datenum(unique(v(ismember(v(:,[2,3]),[1 1],'rows'),[1:3]),'rows'));
z = weekday(a);
dd = bsxfun(@minus,2:8,z - a)';
[lo,ii] = ismember(fix(data(:,1)),dd(:));
ii = ceil(ii/7);
out = accumarray(ii(lo),data(lo,2),[],@(x){[mean(x),max(x)]});
add variant, if "first week" - 1-7 January
v = datevec(timeprac1);
lo = v(:,2) == 1 & ceil(v(:,3)/7) == 1;
[a,~,c] = unique(v(lo,1));
out1 = accumarray(c,P(lo),[],@(x){[mean(x),max(x)]});
out = [a, cell2mat(out)];
third variant, here "first week" - first full week (Mon-Sun) each year's
v = datevec(timeprac1);
a = datenum(unique(v(ismember(v(:,[2,3]),[1 1],'rows'),[1:3]),'rows'));
z = weekday(a);
dd = bsxfun(@plus,a + 9 - z,0:6);
[lo,ii] = ismember(fix(timeprac1),dd(:));
ii = ceil(ii/7);
out = accumarray(ii(lo),P(lo),[],@(x){[mean(x),max(x)]});

6 Kommentare

Andrei Bobrov
Andrei Bobrov am 14 Jul. 2015
Bearbeitet: Andrei Bobrov am 14 Jul. 2015
what is it: v = datevec(timeprac1,P(:,1)); Please see help-doc about datevec.
Please attach your timeprac1 and P.
Andrei Bobrov
Andrei Bobrov am 14 Jul. 2015
corrected
Andrei Bobrov
Andrei Bobrov am 15 Jul. 2015
Asis! datenum - function of MATLAB. Please rename your script C:\Users\datenum.m
Andrei Bobrov
Andrei Bobrov am 15 Jul. 2015
See third variant
Aswas
Aswas am 15 Jul. 2015
Works, thank you very much.
Aswas
Aswas am 17 Jul. 2015
Hi Andrei,
And how can I get only first years max and mean please, not every year?

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Numerical Integration and Differential Equations finden Sie in Hilfe-Center und File Exchange

Tags

Gefragt:

am 14 Jul. 2015

Bearbeitet:

am 18 Jul. 2015

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by