Hi,
I am interested in asking the user to continue the code execution.
If he enters 'Y', it should make the code to run again from the start. Otherwise for 'N' it should stop.
I think, it will start with something like this:
m=input('Do you want to continue, Y/N [Y]:','s')
Please help
Thanks

 Akzeptierte Antwort

Naz
Naz am 30 Nov. 2011

6 Stimmen

Set the infinite loop. I did not check if this code runs, but the idea is this:
while(1)
%%your code here
m=input('Do you want to continue, Y/N [Y]:','s')
if m=='N'
break
end
end
Also, to avoid check up for extra cases from user input I would use function 'menu' instead of 'input':
while(1)
%%your code here
choice = menu('Press yes no','Yes','No');
if choice==2 | choice==0
break;
end
end

2 Kommentare

Naz
Naz am 30 Nov. 2011
You also can create a dummy variable and set it to zero in the 'if' statement:
x=1;
while(x)
if ...
x=0;
end
end
manish sharma
manish sharma am 1 Dez. 2011
Hey Naz,
That worked.
Thanks!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (2)

Image Analyst
Image Analyst am 30 Nov. 2011

6 Stimmen

promptMessage = sprintf('Do you want to Continue processing,\nor Cancel to abort processing?');
button = questdlg(promptMessage, 'Continue', 'Continue', 'Cancel', 'Continue');
if strcmpi(button, 'Cancel')
return; % Or break or continue
end

1 Kommentar

Diana Hunter
Diana Hunter am 22 Mär. 2023
Thank you so much for this. I was having problems with accidentally overwriting exported figures so now I have adapted this so it asks me if I want to export the figure or not, saves a lot of hassle as I always forget to comment it out when I just want to test run the formatting of the figure first.

Melden Sie sich an, um zu kommentieren.

Peyman Obeidy
Peyman Obeidy am 24 Mär. 2017

1 Stimme

%
while(1)
%%your code here
promptMessage = sprintf('Do you want to Continue processing,\nor Cancel to abort processing?');
button = questdlg(promptMessage, 'Continue', 'Continue', 'Terminate', 'Continue');
if strcmpi(button, 'Terminate')
break
end
end

Kategorien

Gefragt:

am 30 Nov. 2011

Kommentiert:

am 22 Mär. 2023

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by