Why won't this for loop move to the next variable?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
On the first pass, everything is fine. i = 49, j = 1, k = 1112. On the second pass, i and j move to the next variables (50 and 18), but k stays at 1112. It does the same thing on the third and fourth pass. Can someone please point out my error? My sincerest gratitude for reading.
for i = 49:52
expiry=find(vifDate==expDate(i));
for j = [1; 18; 43; 63]
vifCls1 = vifCls(j:expiry);
for k = [1112; 1129; 1154; 1174]
consolFut1 = consolFut(k:expDateIdx(i),i);
arbVIF=vifCls1-consolFut1;
end
end
end
0 Kommentare
Antworten (2)
Thorsten
am 30 Jun. 2015
Bearbeitet: Thorsten
am 30 Jun. 2015
I you code only i cycles to the values 49,50, ..., while j and k are always a 4x1 vector [1; 18; 43; 63] and k = [1112; 1129; 1154; 1174]. You have to use row vectors in the for loop:
for j = [1 18 43 63]
% some code
for k = [1112 1129 1154 1174]
0 Kommentare
Star Strider
am 30 Jun. 2015
Your loops probably are incrementing, but because of the way you created your indices, you’re just not seeing it.
Consider:
ix = 1;
for i = 49:52
for j = [1; 18; 43; 63]'
for k = [1112; 1129; 1154; 1174]'
Q(ix,:) = [i j k];
ix = i + 1;
end
end
end
figure(1)
stem3(Q(:,1), Q(:,2), Q(:,3))
grid on
xlabel('i')
ylabel('j')
zlabel('k')
The plot shows that all the loops are incrementing.
2 Kommentare
Star Strider
am 30 Jun. 2015
The column vectors quite definitely do not work (that I found surprising).
I transposed them to demonstrate that even if the loops would increment, it will be difficult to see the result because of the inefficient ways the loops are indexed.
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!