Retrieving indexing of a cell
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Eli Dim
am 29 Jun. 2015
Kommentiert: Eli Dim
am 29 Jun. 2015
I have the variable NameMatrix < nx5 cell > where the number of columns(5) always stays the same and the number of rows(n) changes.
For n=4, NameMatrix looks like this:
'A1' 'A2' 'A3' 'A4' 'A5'
'B1' 'B2' 'B3' 'B4' 'B5'
'C1' 'C2' 'C3' 'C4' 'C5'
'D1' 'D2' 'D3' 'D4' 'D5'
For n=11, NameMatrix looks like this:
'A1' 'A2' 'A3' 'A4' 'A5'
'B1' 'B2' 'B3' 'B4' 'B5'
'C1' 'C2' 'C3' 'C4' 'C5'
'D1' 'D2' 'D3' 'D4' 'D5'
'E1' 'E2' 'E3' 'E4' 'E5'
'F1' 'F2' 'F3' 'F4' 'F5'
'G1' 'G2' 'G3' 'G4' 'G5'
'H1' 'H2' 'H3' 'H4' 'H5'
'I1' 'I2' 'I3' 'I4' 'I5'
'J1' 'J2' 'J3' 'J4' 'J5'
'K1' 'K2' 'K3' 'K4' 'K5'
I do some operations with NameMatrix and as a result for the case where n=11, the new matrix looks like this
'F1'
'F2'
'F3'
'F4'
'F5'
'G1'
'G2'
'G3'
'G4'
'G5'
'H1'
'H2'
'H3'
'H4'
'H5'
'I1'
'I2'
'I3'
'I4'
'I5'
'J1'
'J2'
'J3'
'J4'
'J5'
'K1'
'K2'
'K3'
'K4'
'K5'
'A1'
'A2'
'A3'
'A4'
'A5'
'B1'
'B2'
'B3'
'B4'
'B5'
'C1'
'C2'
'C3'
'C4'
'C5'
'D1'
'D2'
'D3'
'D4'
'D5'
'E1'
'E2'
'E3'
'E4'
'E5'
I would like to extract the indices of this new matrix. So F1 = 26, F2 =27, F3=28, F4=29, F5=30, G1=31, G2=32, G3=33, etc. SO i get a new vector which looks like this [26 27 28 29 30 31 32 33....] for an arbitrary number of rows n. Which would be the best way to do this?
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Guillaume
am 29 Jun. 2015
Note that linear indices in matlab are per column rather than per row (so the indices of 'F1', 'F2', F3', etc. would be [6, 17, 28, ...]. If you do want [26, 27, ...] you'll have to transpose your initial matrix:
c = {'A1' 'A2' 'A3' 'A4' 'A5'
'B1' 'B2' 'B3' 'B4' 'B5'
'C1' 'C2' 'C3' 'C4' 'C5'
'D1' 'D2' 'D3' 'D4' 'D5'
'E1' 'E2' 'E3' 'E4' 'E5'
'F1' 'F2' 'F3' 'F4' 'F5'
'G1' 'G2' 'G3' 'G4' 'G5'
'H1' 'H2' 'H3' 'H4' 'H5'
'I1' 'I2' 'I3' 'I4' 'I5'
'J1' 'J2' 'J3' 'J4' 'J5'
'K1' 'K2' 'K3' 'K4' 'K5'};
cc = {'F1' 'F2' 'F3' 'F4' 'F5' 'G1' 'G2' 'G3' 'G4' 'G5' 'H1' 'H2' 'H3' 'H4'}';
[~, indices] = ismember(cc, c) %transpose c to get [26 27 ...]
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