Split a matrix in rows according to a vector
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Eli Dim
am 28 Jun. 2015
Beantwortet: Star Strider
am 28 Jun. 2015
Hello, If I have a matrix that looks like this:
A = [
[1, 0, 0, 5, 10, 5, 100, 300];
[1, 0, 0, 5, 10, 5, 100, 400];
[1, 0, 0, 5, 10, 5, 100, 450];
[1, 0, 0, 5, 10, 5, 100, 500];
[1, 0, 0, 5, 10, 5, 100, 550];
[1, 0, 0, 5, 10, 5, 100, 600];
[1, 0, 0, 5, 10, 5, 100, 700];
[1, 0, 0, 4, 10, 4, 100, 300];
[1, 0, 0, 5, 10, 5, 100, 450];
[1, 0, 0, 5, 10, 5, 100, 800];
];
and a vector that looks like this:
B = [ 1; 2; 1; 3; 2;1];
How can I split my matrix A according to this rule: The first sub-matrix A has a row number equal to the first value of B The second sub-matrix A has a row number equal to the second value of B etc. I would like to store the split sub-matrices in separate cells. So essentially, the first cell will look like this: 1, 0, 0, 5, 10, 5, 100, 300 the second cell will look like this:
1, 0, 0, 5, 10, 5, 100, 400
1, 0, 0, 5, 10, 5, 100, 450
0 Kommentare
Akzeptierte Antwort
Star Strider
am 28 Jun. 2015
I would use mat2cell:
C = mat2cell(A, B, size(A,2));
C1 = C{1} % View Result
C2 = C{2} % View Result
C1 =
1 0 0 5 10 5 100 300
C2 =
1 0 0 5 10 5 100 400
1 0 0 5 10 5 100 450
0 Kommentare
Weitere Antworten (1)
Azzi Abdelmalek
am 28 Jun. 2015
x=cumsum(B)-B+1
y=cumsum(B)
out=arrayfun(@(ii,jj) A(ii:jj,:),x,y,'un',0)
0 Kommentare
Siehe auch
Kategorien
Mehr zu Data Types finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!