Split a matrix in rows according to a vector

Hello, If I have a matrix that looks like this:

A = [
[1, 0, 0, 5, 10, 5, 100, 300];
[1, 0, 0, 5, 10, 5, 100, 400];
[1, 0, 0, 5, 10, 5, 100, 450];
[1, 0, 0, 5, 10, 5, 100, 500];
[1, 0, 0, 5, 10, 5, 100, 550];
[1, 0, 0, 5, 10, 5, 100, 600];
[1, 0, 0, 5, 10, 5, 100, 700];
[1, 0, 0, 4, 10, 4, 100, 300];
[1, 0, 0, 5, 10, 5, 100, 450];
[1, 0, 0, 5, 10, 5, 100, 800];
];

and a vector that looks like this:

B = [ 1; 2; 1; 3; 2;1];

How can I split my matrix A according to this rule: The first sub-matrix A has a row number equal to the first value of B The second sub-matrix A has a row number equal to the second value of B etc. I would like to store the split sub-matrices in separate cells. So essentially, the first cell will look like this: 1, 0, 0, 5, 10, 5, 100, 300 the second cell will look like this:

   1, 0, 0, 5, 10, 5, 100, 400
   1, 0, 0, 5, 10, 5, 100, 450

Answer 1

[Star Strider]

I would use mat2cell:

C = mat2cell(A, B, size(A,2));
C1 = C{1}                           % View Result
C2 = C{2}                           % View Result

C1 =

       1     0     0     5    10     5   100   300

C2 =

       1     0     0     5    10     5   100   400
       1     0     0     5    10     5   100   450

Answer 2

[Azzi Abdelmalek]

x=cumsum(B)-B+1
y=cumsum(B)
out=arrayfun(@(ii,jj) A(ii:jj,:),x,y,'un',0)