help me with this for loop please

 x = -10:0.1:10;

 y = 0:0.005:1;

 minNmax1 = 0:.005:1;

 upper_1 = 0:.005:1;

 y2 = 0:.005:1;

 f1 = trapmf(x,[-2 0 0 2].');

 minNmax1 = zeros(length(x), 2);

 for k = 1 :length(y)

     minNmax1(k,:) = [min(x),max(x)];

 end

I'm trying to get [min(x),max(x)] for 201 values of y but this will only give me 1 answer [-10 10] which i assume is the first iteration?

help!

[Katalin]

Sorry it is not clear what you would like in your variable. min(x) and max(x) are both constants, it will fill your 201x2 matrix with -10 in the first column and 10 in the second. Could you please explain more what you would like to achieve?

[soloby]

hi, thanks for the reply.

I'm trying to get minimum and maximum values of my function f1 (triangular tooth) for 200 different values of y.

i.e.,

@ y = 0 min(x), max(x)

@ y = 0.005 min(x), max(x)

@ y = 0.01 min(x), max(x)

and so forth. all the way up to y = 1

[Jan]

I cannot understand your notation. What does "@ y = 0.01 min(x), max(x)" mean? There is no "y" in this expression on the right hand side. What does the "y=0.01" part mean? Which y-values do you want to check and do you think that any y-value is exactly 0.01?

Perhaps you want "f1" to appear anywhere?

[Katalin]

How does f1 depend on y?

[soloby]

my function f1 ranges from 0 to 1. if you plot(x,f1) it can be seen.

I need to split my f1 values (0 to 1) into 201 pieces and find the upper and lower x values for each iterations of y. Think of fuzzy logic, it is similar to how it is solved.

Easy concept, but I'm afraid a lot harder to execute.

so my f1 is 0 to 1

I want to divide it up into equal numbers (201 in my case)

at each iteration, I want to find the x values Please someone help!

[soloby]

Check my picture please, I need to find those starred points for all the red lines (201 of them)

Answer 1

[Muhannad]

will min(x) always be the same number as x is not changing? you can use repmat(min(x), 201,1)) if that is the case

[soloby]

min(x) will be the same for each iterations of y but I need it for all 201 y's.