d(phi)/dt=​laplaciano​(-phi+phi^​3-laplacia​no(phi)) given boundary conditions and a initial state (strange result)

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DDD
DDD am 2 Jun. 2015
Kommentiert: DDD am 2 Jun. 2015
It is given d(phi)/dt=laplaciano(-phi+phi^3-laplaciano(phi)) to solve in a square 30*30 (L=30).
It is also mentioned that phi(1, y) = 1 and phi(L, y) =

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