Filter löschen
Filter löschen

Too many output arguments error in my code

2 Ansichten (letzte 30 Tage)
Robert
Robert am 2 Jun. 2015
Bearbeitet: Stephen23 am 2 Jun. 2015
I have the following code, I am trying to get all of the wavelet approximations out (it works fine with details, but not approximations).
I know what the error means, I just can't figure out how it applies in my code.
GRACE = load ('GRACE.txt')
ncol = size(GRACE,2);
for k = 1:ncol
[c,l] = wavedec(GRACE(:,k),6,'dmey');
cA6 = appcoef(c,l,'dmey',6);
[cD1,cD2,cD3,cD4,cD5,cD6] = appcoef(c,l,[1,2,3,4,5,6]);
D = [];
D(:,6) = wrcoef('d',c,l,'dmey',6);
D(:,5) = wrcoef('d',c,l,'dmey',5);
D(:,4) = wrcoef('d',c,l,'dmey',4);
D(:,3) = wrcoef('d',c,l,'dmey',3);
D(:,2) = wrcoef('d',c,l,'dmey',2);
D(:,1) = wrcoef('d',c,l,'dmey',1);
filename = sprintf('%s_%04f.txt', 'GRACE_APROXIMATIONS', k)
csvwrite(filename,D)
end
Any help would be greatly appreciated

Antworten (1)

Walter Roberson
Walter Roberson am 2 Jun. 2015
Bearbeitet: Walter Roberson am 2 Jun. 2015
appcoef() only ever returns one variable. You are trying to get it to return 6.
If you are not passing a string representing the wavelet name, then you should be using either 4 or 5 arguments, with the 3rd and 4th being filters. Your [1,2,3,4,5,6] is being interpreted as a filter.
You cannot pass in a list of levels and get one output variable for each.
  4 Kommentare
Robert
Robert am 2 Jun. 2015
So something like this? This is my best interpretation of what you suggest, Still I get the same error, am I on the right path?
GRACE = load ('GRACE.txt')
ncol = size(GRACE,2);
for k = 1:ncol
[c,l] = wavedec(GRACE(:,k),6,'dmey');
cA1 = appcoef(c,l,'dmey',1);
cA2 = appcoef(c,l,'dmey',2);
cA3 = appcoef(c,l,'dmey',3);
cA4 = appcoef(c,l,'dmey',4);
cA5 = appcoef(c,l,'dmey',5);
cA6 = appcoef(c,l,'dmey',6);
[cA1,cA2,cA3,cA4,cA5,cA6] = appcoef(c,l,[1,2,3,4,5,6]);
D = [];
D(:,6) = wrcoef('d',c,l,'dmey',6);
D(:,5) = wrcoef('d',c,l,'dmey',5);
D(:,4) = wrcoef('d',c,l,'dmey',4);
D(:,3) = wrcoef('d',c,l,'dmey',3);
D(:,2) = wrcoef('d',c,l,'dmey',2);
D(:,1) = wrcoef('d',c,l,'dmey',1);
filename = sprintf('%s_%04f.txt', 'GRACE_APROXIMATIONS', k)
csvwrite(filename,D)
end
if true
% code
end
Stephen23
Stephen23 am 2 Jun. 2015
Bearbeitet: Stephen23 am 2 Jun. 2015
@Robert: the appcoef documentation shows these syntaxes:
A = appcoef(C,L,'wname',N)
A = appcoef(C,L,'wname')
A = appcoef(C,L,Lo_R,Hi_R)
A = appcoef(C,L,Lo_R,Hi_R,N)
Count the outputs: each syntax shows exactly one output. You wrote this:
[cA1,cA2,cA3,cA4,cA5,cA6] = appcoef(c,l,[1,2,3,4,5,6]);
Count the outputs: there are six of them. The error message is telling you that you have too many outputs for this function: appcoef provides only one output.
To fix this you have to call appcoef in a loop, as Walter Roberson wrote.

Melden Sie sich an, um zu kommentieren.

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by