Filter löschen
Filter löschen

Why do I get different value for pole placement function?

2 Ansichten (letzte 30 Tage)
Folks,
I need to design a state variable feedback regulator for following discrete time closed-loop system with a pair of complex poles at 0.3+i0.4 and 0.3-j0.4 .
For which I am using Ackermann’s formula as below:
Since we know about the location of desired poles, hence:
And to implement above equation in Matlab, I use following:
p1=0.3 + 0.4*1i;
p2=0.3 - 0.4*1i;
P_z=(z-p1)*(z-p2);
P_phi=eval(subs(P_z,z,phi));
K1=[0 1]*([gamma,phi*gamma]\P_phi);
Result:
K1 =
-1463.39992735389 274.509346733496
But, if I use Matlab's place command instead, I get different result:
K2=place(phi,gamma,[p1 p2]);
Result:
K2 =
321.895478432477 -36.132432596429
Can someone please tell me why I get distinct values for K1 and K2 whereas I am expecting to get the same result for both

Akzeptierte Antwort

Azzi Abdelmalek
Azzi Abdelmalek am 25 Mai 2015
Your code is not correct
gamma=[0;0.9948*10^(-4)]
phi=[1 0.0001;-0.0503 0.9896]
e=[0 1]*inv([gamma fi*gamma])
p1=0.3 + 0.4*1i;
p2=0.3 - 0.4*1i;
alpha=fliplr(poly([p1,p2]))
k1=alpha(1)*e+alpha(2)*e*phi+e*phi^2
k2=place(phi,gamma,[p1 p2])
  2 Kommentare
Hasan Ghorbani
Hasan Ghorbani am 25 Mai 2015
Thank you so much for your answer. fliplr was redundant though. Following code worked beautifully:
P_z = poly([p1,p2]);
P_phi = P_z(1)*(phi^2) + P_z(2)*(phi^1) + P_z(3)*(phi^0);
K = [0 1] * inv([gamma,phi*gamma]) * P_phi;
Walter Roberson
Walter Roberson am 26 Mai 2015
[0 1] / [gamma,phi*gamma] * P_phi would be more numerically stable

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Control System Toolbox finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by