Using parfor loop with fetchNext
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Poul-Erik Hansen
am 15 Aug. 2025 um 13:46
Kommentiert: Poul-Erik Hansen
am 18 Aug. 2025 um 8:58
Hi
I have a parallel calculations of eigenvalues using parfeval and fetching of the eigenvalues using fetchNext. The code runs fine as long as I have a serial readout of the eigenvalus and eigenvectors stored in f. However, this is rater slow and I want to make a parallel readout using a parfor loop instead of the for loop in the code below.However, I get the erro unable to classify eigMtr.
L=20;
NumOfSlabs=50;
eigMtr=zeros(2*L,2*NumOfSlabs*L,'single');
W=eigMtr;
W_1=zeros(L,2*NumOfSlabs*L,'single');W_2=W_1;
f(1:NumOfSlabs) = parallel.FevalFuture;
for idx = 1:NumOfSlabs
[CompletedIdx, Wt,Dt] = fetchNext(f);
start=1+(CompletedIdx-1)*2*L;stop=2*CompletedIdx*L;
eigMtr(1:2*L,start:stop)=sqrt(Dt);
W1=Wt(1:L,:);
W2=Wt(L+1:2*L,:);
W_1(:,start:stop)=W1;
W_2(:,start:stop)=W2;
W(1:L,start:stop)=W2;
W(L+1:2*L,start:stop)=W1;
clear Wt Dt W1 W2
end
Thanks
Poul-Erik
0 Kommentare
Antworten (1)
Walter Roberson
am 15 Aug. 2025 um 19:02
For all variables output from parfor, the indices must be a mix of constants and expressions involving constants defined simply before the parfor starts, together with simple expressions involving the parfor index variable.
Your code does not index by the parfor index variable; instead it tries to index by the computed start and stop which are not constants.
There is no way for parfor to prove that each portion of the matrix will be written to at most once, so it bans the operation.
You might (somehow) know that the returned CompletedIdx are unique positive integers, but there is no way for parfor to know it.
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