Hi guys,
I have the following set of data:
sigma=[0;0;0;0;0;1;1;1;1;1;2;2;2;2;2];
alpha=[0;1;2;3;4;0;1;2;3;4;0;1;2;3;4];
C=[10;11;12;13;14;15;16;17;18;19;20;21;22;23;24];
Now I want to know wat the value of C is if my calculate alpha is 2.5 and sigma is 1.5.
To solve this problem, I have tried to use the function interp2. But I get an error.
Can somebody help me with this?
Thanks in advance, Bas Siebers

 Akzeptierte Antwort

Star Strider
Star Strider am 21 Mai 2015
Use the scatteredInterpolant function:
sigma=[0;0;0;0;0;1;1;1;1;1;2;2;2;2;2];
alpha=[0;1;2;3;4;0;1;2;3;4;0;1;2;3;4];
C=[10;11;12;13;14;15;16;17;18;19;20;21;22;23;24];
F = scatteredInterpolant(sigma, alpha, C);
Cnew = F(1.5, 2.5);
figure(1)
stem3(sigma, alpha, C)
hold on
stem3(2.5, 1.5, Cnew, 'r')
hold off
grid on
xlabel('\sigma')
ylabel('\alpha')
It plots ‘Cnew’, your interpolated value for ‘C’, in red.

2 Kommentare

Thanks, this exactly what i was looking for
My pleasure!

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Weitere Antworten (2)

John D'Errico
John D'Errico am 21 Mai 2015
Bearbeitet: John D'Errico am 21 Mai 2015
sigma=[0;0;0;0;0;1;1;1;1;1;2;2;2;2;2];
alpha=[0;1;2;3;4;0;1;2;3;4;0;1;2;3;4];
C=[10;11;12;13;14;15;16;17;18;19;20;21;22;23;24];
You have nicely gridded data already. Reshape will suffice to make it into a 2-d array. This is probably why you had an error, because you had the data strung out into vectors.
sigma = reshape(sigma,5,3);
alpha = reshape(alpha,5,3);
C = reshape(C,5,3);
So now we can plot C.
surf(sigma,alpha,C)
And interp2 will now work properly.
interp2(sigma,alpha,C,1.5,2.5)
ans =
20
It is important to understand that scatteredInterpolant is not needed, because your data is completely gridded already. That makes scatteredInterpolant less efficient than need be otherwise. As well, interp2 allows you to use a spline interpolant if you so desire, whereas scatterdInterpolant is limited to at most a linear interpolant. griddedInterpolant does allow the alternative (smoother) methods for interpolation.
In fact, interp2 looks to be something that MAY eventually be replaced by griddedInterpolant, at least they seem to be making hints along those lines in the help.
Andrei Bobrov
Andrei Bobrov am 21 Mai 2015
Bearbeitet: Andrei Bobrov am 21 Mai 2015
[y,x] = ndgrid(unique(alpha),unique(sigma));
v = reshape(C,size(x));
f = griddedInterpolant(x,y,v);
example of using:
>>f(1.5,2.5)

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