quadgk AbsTol/RelTol parameters combinations

2 Ansichten (letzte 30 Tage)
Alejandro
Alejandro am 14 Apr. 2025
Kommentiert: Alejandro am 19 Apr. 2025
Dear network.
I am having trouble getting the desired result of an integral involving Bessel functions Jo and Yo.
Need your help with a powerful set of combinations of the AbsTol/RelTol parameters that will help me get a low-error result
This is the equation I am trying to solve, with t as a parameter:
  2 Kommentare
Torsten
Torsten am 15 Apr. 2025
What is "the desired result" ? Do you have integral values of high precision to compare with ?
Alejandro
Alejandro am 15 Apr. 2025
Hi Torsten, yes.
I have figures from various papers and books to compare with.
The current results I am obtaining in MATLAB using either the quadgk or integral commands are off by +- 10%, which requires an optimization of the AbsTol/RelTol parameters.

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Torsten
Torsten am 15 Apr. 2025
Bearbeitet: Torsten am 15 Apr. 2025
umin = 1e-16;
f = @(t,u) exp(-t*u.^2)./(u.*(besselj(0,u).^2+bessely(0,u).^2));
g = @(u) pi/2 * atan((2*double(eulergamma)-log(4)+2*log(u))/pi);
qD = @(t) 1 + 4/pi^2*( g(umin) + quadgk(@(u)f(t,u),umin,Inf) );
format long
t = 0.1:0.1:10;
plot(t,arrayfun(@(t)qD(t),t))
xlabel('t')
ylabel('qD')
grid on
  3 Kommentare
Torsten
Torsten am 16 Apr. 2025
Bearbeitet: Torsten am 16 Apr. 2025
Consider
syms u
f = u*(bessely(0,u)^2+1);
f = 
series(f)
ans = 
g = u*(4*(eulergamma-log(sym('2'))+log(u))^2/sym(pi)^2+1)
g = 
int(1/g)
ans = 
Limit for int(1/g) as u -> 0+ is pi/2 * atan(-Inf) = -pi^2/4.
Thus for f(t,u) = exp(-t*u.^2)./(u.*(besselj(0,u).^2+bessely(0,u).^2)) I computed
int(f,0,Inf) = int(f,0,umin) + int(f,umin,Inf) ~ int(1/g,0,umin) + int(f,umin,Inf) = pi/2*atan((2*eulergamma-log(4)+2*log(umin))/pi) + pi^2/4 + int(f,umin,Inf)
Now multiply by 4/pi^2 to get qD.
Alejandro
Alejandro am 19 Apr. 2025
Thanks for your useful feedback Torsten. Will generate the values and compere against my reference tables.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Special Functions finden Sie in Help Center und File Exchange

Produkte


Version

R2024b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by