Represent data with a status bar plot

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Nicolas
Nicolas am 4 Mär. 2025
Kommentiert: Nicolas am 6 Mär. 2025
Hello everyone!
I'm looking for a way to represent my data in the form of a status bar, the colour of which depends on the value.
The end result should look something like this
Does anyone know the function that plots something like this?

Akzeptierte Antwort

Voss
Voss am 4 Mär. 2025
t = load('mydata.mat').mydata;
X = repmat(double(t.Time(:)),1,2);
C = repmat(double(t.Data(:)),1,2);
Y = zeros(size(X))+[0 1];
figure('Position',[1 1 900 600])
tiledlayout(2,2)
nexttile
plot(t.Time,t.Data)
xlim(t.Time([1 end]))
title(sprintf('line plot:\nentire timeseries'))
nexttile
plot(t.Time,t.Data)
xlim([0 40])
title(sprintf('line plot:\nzoomed to beginning'))
nexttile
surface(X,Y,C,'EdgeColor','none')
xlim(X([1 end],1))
ylim(Y(1)+[-0.5 1.5])
colorbar
title(sprintf('status-bar plot:\nentire timeseries'))
nexttile
surface(X,Y,C,'EdgeColor','none')
xlim([0 40])
ylim(Y(1)+[-0.5 1.5])
colorbar
title(sprintf('status-bar plot:\nzoomed to beginning'))
  4 Kommentare
Voss
Voss am 5 Mär. 2025
Here's one approach you can use to add the enumerated data (text objects):
t = load('mydata.mat').mydata;
X = repmat(double(t.Time(:)),1,2);
C = repmat(double(t.Data(:)),1,2);
Z = zeros(size(X));
Y = Z+[0 1];
[G,GID] = findgroups(t.Data);
NG = numel(GID);
XT = zeros(NG,1);
for ii = 1:NG
XT(ii) = mean(t.Time(G == ii));
end
YT = (Y(1,1)+Y(1,2))/2*ones(NG,1);
ST = string(GID);
args = {'HorizontalAlignment','center','Color','w','FontSize',14};
figure('Position',[1 1 900 600],'Color',[0.94,0.94,0.94])
tiledlayout(2,1)
nexttile
surface(X,Y,Z,C,'EdgeColor','none')
text(XT,YT,ST,args{:})
xlim(X([1 end],1))
ylim(Y(1,:)+[-0.5 0.5])
colorbar
title(sprintf('status-bar plot:\nentire timeseries'))
nexttile
surface(X,Y,Z,C,'EdgeColor','none')
text(XT,YT,ST,args{:})
xlim([0 40])
ylim(Y(1,:)+[-0.5 0.5])
colorbar
title(sprintf('status-bar plot:\nzoomed to beginning'))
Nicolas
Nicolas am 6 Mär. 2025
Great idea ! Here is the final result after including some text :
t = load('mydata.mat').mydata;
X = repmat(double(t.Time(:)),1,2);
C = repmat(double(t.Data(:)),1,2);
Z = zeros(size(X));
Y = Z+[0 1];
[G,GID] = findgroups(t.Data);
NG = numel(GID);
XT = zeros(NG,1);
ST_text = ["0 - a";"1 - b";"2 - c";"3 - d";"4 - e";"5 - f";"6 - g";"7 - h";"8 - i";"9 - j";"10 - k";"11 - l";"12 - m";"13 - n"; "14 - o"];
for ii = 1:NG
XT(ii) = mean(t.Time(G == ii));
enum_name(ii) = ST_text(GID(ii)+1);
end
YT = (Y(1,1)+Y(1,2))/2*ones(NG,1);
ST = enum_name;
args = {'HorizontalAlignment','center','Color','w','FontSize',14,'Rotation',90};
figure1 = figure('Position',[1 1 900 600],'Color',[0.94,0.94,0.94]);
surface(X,Y,Z,C,'EdgeColor','none')
text(XT,YT,ST,args{:})
xlim(X([1 end],1))
ylim(Y(1,:)+[-0.1 0.1])
clim([0 14])
colorbar('Ticks',[0 1 2 3 4 5 6 7 8 9 10 11 12 13],...
'TickLabels',{'0 - a','1 - b','2 - c','3 - d','4 - e','5 - f','6 - g','7 - h','8 - i','9 - j','10 - k - l','12 - m','13 - n', '14 - o'},...
'Location','southoutside');
(I've used a different data run, to make it easier to read)
Thank you again @Voss for your support !

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Weitere Antworten (1)

Aquatris
Aquatris am 4 Mär. 2025
You can use bar() function with 'stacked' argument;
y = [30 50 10 10];
barh(1,y,"stacked");
  2 Kommentare
Nicolas
Nicolas am 4 Mär. 2025
Hello @Aquatris and thank you for your reply!
Unfortunately I omitted some details in my request ... I work with timeseries, so I can't really use this method, I'd first have to determine the value groups (1,2,3 etc ...) before being able to display them in stacked bar.
Aquatris
Aquatris am 4 Mär. 2025
I think you should provide your data and show exactly what you want.

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