Filter löschen
Filter löschen

How can I solve this system of equations?

2 Ansichten (letzte 30 Tage)
Lorena Ortiz
Lorena Ortiz am 18 Mai 2015
Kommentiert: Lorena Ortiz am 18 Mai 2015
I'm trying to solve a system of equations of two equations with two unknowns but Matlab has been running for an hour and it is still showing busy and I hence I have no results. Is Matlab able to solve systems like this?
syms c_d c_e V_d;
ec1='0.9259259259e-2*sqrt(1/2+(1/2)*sqrt(1+2328.331561*c_d^2))+(sqrt(1/2+(1/2)*sqrt(1+c_e^2))*sinh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2)))-sqrt(-1/2+(1/2)*sqrt(1+c_e^2))*sin(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_e^2))))/(cosh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2)))+cos(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_e^2))))+(.2000000000*(2.521200000*10^10*A*sech(A)^2+2.489400000*10^10*tanh(A)))*(-0.9259259259e-2*sqrt(-1/2+(1/2)*sqrt(1+2328.331561*c_d^2))+(-sqrt(1/2+(1/2)*sqrt(1+c_e^2))*sin(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_e^2)))-sqrt(-1/2+(1/2)*sqrt(1+c_e^2))*sinh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2))))/(cosh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2)))+cos(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_d^2)))))/(3.750000000*10^10*A*sech(A)^2+3.750000000*10^10*tanh(A)+1.590000000*10^8*tanh(A)^2)=1.528755555*10^7*V_d*((2.500000000*(A*sech(A)^2+tanh(A)))/sqrt(1/2+(1/2)*sqrt(1+2328.331561*c_d^2))-tanh(A)*(-sqrt(1/2+(1/2)*sqrt(1+c_e^2))*sin(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_e^2)))-sqrt(-1/2+(1/2)*sqrt(1+c_e^2))*sinh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2))))/(sqrt(1/2+(1/2)*sqrt(1+c_e^2))*sqrt(-1/2+(1/2)*sqrt(1+c_e^2))*(cosh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2)))+cos(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_e^2))))))/(3.750000000*10^10*A*sech(A)^2+3.750000000*10^10*tanh(A)+1.590000000*10^8*tanh(A)^2)';
ec2='-0.9259259259e-2*sqrt(-1/2+(1/2)*sqrt(1+2328.331561*c_d^2))+(-sqrt(1/2+(1/2)*sqrt(1+c_e^2))*sin(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_e^2)))-sqrt(-1/2+(1/2)*sqrt(1+c_e^2))*sinh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2))))/(cosh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2)))+cos(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_e^2))))-(.2000000000*(2.521200000*10^10*A*sech(A)^2+2.489400000*10^10*tanh(A)))*(0.9259259259e-2*sqrt(1/2+(1/2)*sqrt(1+2328.331561*c_d^2))+(sqrt(1/2+(1/2)*sqrt(1+c_e^2))*sinh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2)))-sqrt(-1/2+(1/2)*sqrt(1+c_e^2))*sin(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_e^2))))/(cosh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2)))+cos(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_e^2)))))/(3.750000000*10^10*A*sech(A)^2+3.750000000*10^10*tanh(A)+1.590000000*10^8*tanh(A)^2) = -1.528755555*10^7*V_d*(-2.500000000*sqrt(-1/2+(1/2)*sqrt(1+2328.331561*c_d^2))*(A*sech(A)^2+tanh(A))/(sqrt(1/2+(1/2)*sqrt(1+2328.331561*c_d^2))*(sqrt(1/2+(1/2)*sqrt(1+2328.331561*c_d^2))+1))-tanh(A)*(sqrt(1/2+(1/2)*sqrt(1+c_e^2))*sinh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2)))-sqrt(-1/2+(1/2)*sqrt(1+c_e^2))*sin(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_e^2)))-tanh(A)*(cosh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2)))+cos(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_e^2)))))/(sqrt(1/2+(1/2)*sqrt(1+c_e^2))*sqrt(-1/2+(1/2)*sqrt(1+c_e^2))*(cosh(2*A*sqrt(1/2+(1/2)*sqrt(1+c_e^2)))-cos(2*A*sqrt(-1/2+(1/2)*sqrt(1+c_e^2))))))/(3.750000000*10^10*A*sech(A)^2+3.750000000*10^10*tanh(A)+1.590000000*10^8*tanh(A)^2)';
[c1 c2]=solve(ec1,ec2,c_d,c_e)
Thank you!

Antworten (1)

Torsten
Torsten am 18 Mai 2015
Maybe numerically, but not symbolically.
Try fsolve.
Best wishes
Torsten.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by