How do I integrate a piecewise function with an upper bound variable
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As shown in the code, the Angle function alpha is a piecewise function with respect to r (the others are known sign values), and it can be performed as an indeterminate integral or a definite integral of a definite value, but it cannot be calculated when the upper limit of the integral is the variable r. The error message is that the continuity of the function in the integral interval cannot be determined.
...
syms r alpha(r)
alpha(r) = piecewise((r >= part_p(1, 1)) & (r <= part_p(2, 1)), alpha_part(1));
for i = 2:11
alpha(r) = piecewise((r > part_p(2*i-2, 1)) & (r <= part_p(2*i-1, 1)),...
atan(((-1)^(mod(i, 2)) * (r - cir_x(i)) / sqrt(cir_r(i)^2 - (r - cir_x(i))^2))), alpha(r));
alpha(r) = piecewise((r > part_p(2*i-1, 1)) & (r <= part_p(2*i, 1)),...
alpha_part(i), alpha(r));
end
syms arcLength(r)
arcLength(r) = int(sqrt(tan(alpha)^2 + 1), [part_p(1, 1), r]);
5 Kommentare
Please provide the full code that doesn't result in any errors
syms r alpha(r)
alpha(r) = piecewise((r >= part_p(1, 1)) & (r <= part_p(2, 1)), alpha_part(1));
for i = 2:11
alpha(r) = piecewise((r > part_p(2*i-2, 1)) & (r <= part_p(2*i-1, 1)),...
atan(((-1)^(mod(i, 2)) * (r - cir_x(i)) / sqrt(cir_r(i)^2 - (r - cir_x(i))^2))), alpha(r));
alpha(r) = piecewise((r > part_p(2*i-1, 1)) & (r <= part_p(2*i, 1)),...
alpha_part(i), alpha(r));
end
syms arcLength(r)
arcLength(r) = int(sqrt(tan(alpha)^2 + 1), [part_p(1, 1), r]);
Walter Roberson
am 15 Dez. 2024
I would suggest a different method for constructing the piecewise polynomial:
Construct a cell array C that is 2 x 11. Make the first row the conditions (r > part_p(2*i-2, 1)) & (r <= part_p(2*i-1, 1) . Make tthe second row the value corresponding to the conditions, mostly atan(((-1)^(mod(i, 2)) * (r - cir_x(i)) / sqrt(cir_r(i)^2 - (r - cir_x(i))^2)))
Now
alpha = piecewise(C{:})
You can reduce the work a lot by using
num2cell(r >= part_p(1:2:end) & r <= part_p(2:2:end))
and
i = 2:11;
num2cell(atan(((-1).^(mod(i, 2)) .* (r - cir_x(i)) ./ sqrt(cir_r(i).^2 - (r - cir_x(i)).^2))))
Sam Chak
am 16 Dez. 2024
It is somewhat difficult to interpret the lines from a mathematician's perspective. Therefore, I attempted to separate them. The sub-functions of part_p() and alpha_part() are unknown. Are they mathematically defined, or do they refer to a table (cell) from which you extract fixed values?
syms alpha(r)
condition_1 = r >= part_p(1, 1); % condition 1
condition_2 = r <= part_p(2, 1); % condition 2
outcome = alpha_part(1); % outcome
%% Piecewise function
alpha(r) = piecewise(condition_1 & condition_2, outcome);
沐欣
am 17 Dez. 2024
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