Does anybody now a workaround for this behaviour of vpa?:
syms a b c
c=a+b; a=1; b=1;
vpa(c)
ans =
a + b
while
vpa(a+b)
returns the expected ans=2. I know I could define c after a and b, but in my particular program (the above is just a minimal example), this is not possible. So I am looking for a simple workaround (vpa(char(c)) also does not work).

 Akzeptierte Antwort

Star Strider
Star Strider am 14 Mai 2015

0 Stimmen

Use the subs function inside the vpa call:
syms a b c
c=a+b; a=1; b=1;
vpa(subs(c))
produces:
ans =
2.0

2 Kommentare

lvn
lvn am 14 Mai 2015
Thanks so much, works great!
Star Strider
Star Strider am 14 Mai 2015
My pleasure!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by