error in matlab function

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studentU
studentU am 12 Mai 2015
Kommentiert: Walter Roberson am 13 Mai 2015
hello,
I have a problem in matlab function block, where I use the trigonometric function, conversion function (ex:degtorad..) ... when I simulates a first part it works, but once I pass execter:
x = degtorad (var);
s = cos (x) * 2
... that it generated this error :
Expected Either a logical, char, int, fi, single, double gold. Found a MATLAB type. MATLAB kinds are returned from calls to the MATLAB interpreter and are not supported inside expressions. They May only be used on the right-hand side of assignments and have arguments to MATLAB calls.
can u help me?

Antworten (3)

Walter Roberson
Walter Roberson am 12 Mai 2015
Try
cx = cos(x);
s = cx * 2;

studentU
studentU am 12 Mai 2015
Bearbeitet: Walter Roberson am 12 Mai 2015
thank's for your reply,
it solves some but for:
f = cos (var) * sin (var) * cos (arg) + sin (var) * cos (arg);
I proceed in the same manner: vc = cos (var) .. then F1=vc*vs*ca;.. and f = F1 + F2;
but it generates mismatch Size!!
  1 Kommentar
Walter Roberson
Walter Roberson am 12 Mai 2015
You probably need to use .* instead of *
F1 = vc .* vs .* ca;

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studentU
studentU am 12 Mai 2015
yes I used it but it does not solve the problem :/
  1 Kommentar
Walter Roberson
Walter Roberson am 13 Mai 2015
Your var and your arg are not the same size and your arg is not scalar.
You need to define what size of output you want for that case.
Code would help.
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