Generate a vector with elements based on certain elements in another vector

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Bob
Bob am 30 Okt. 2024 um 8:26
Kommentiert: Bob am 30 Okt. 2024 um 11:46
I have a simple question but do not know the code that will give me the answer. Can you help me with this? I would like to create a vector B with the same length as A. The elements in B should be zero, except for the first n elements after a certain value appears at the ih-th position in vector A.
For example, vector B should contain the value 1 for three following positions when the first 1 appears in A. This means that vector B = [0;0;0;0;0;1;1;1;0;0] if A = [0;0;0;0;0;1;1;1;1;1].

Antworten (2)

Alan Stevens
Alan Stevens am 30 Okt. 2024 um 9:08
Like this?
A = [0;0;0;0;0;1;1;1;1;1];
B =zeros(size(A));
ptr = find(A==1);
B(ptr(1):ptr(1)+2)=1
B = 10×1
0 0 0 0 0 1 1 1 0 0
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  1 Kommentar
Bob
Bob am 30 Okt. 2024 um 11:45
Yes, this is the solution. Thank you.
However, I would like to use a for loop with an if statement. Is this possible? Can you help me with this?

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Shantanu Dixit
Shantanu Dixit am 30 Okt. 2024 um 10:32
Bearbeitet: Shantanu Dixit am 30 Okt. 2024 um 10:35
Hi Bob,
You can achieve the conditional vector by first creating a vector 'B' initialized to zeros and then assigning the value 1 to elements following the first occurrence of 1 in vector 'A'.
  • Use 'find' function to get the index ('ih') of the first occurrence of 1 in vector A.
  • Initialize 'B' as a zero vector of the same length as 'A'.
  • Set the next 'n' elements in 'B' to 1 starting from 'ih' by indexing (ensure indexing remains within array bounds)
I hope this helps!
You can refer to the MATLAB Onramp course to gain understanding on basic vector creation and indexing: https://matlabacademy.mathworks.com/details/matlab-onramp/gettingstarted
Also refer to the MathWorks documentation on following useful functions:

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