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simple math question

4 Ansichten (letzte 30 Tage)
LIU WEIHUA
LIU WEIHUA am 18 Nov. 2011
There has a function can be written as: y=H*[X,Y,1]'. where [X,Y,1]is known constants. I want finding the derivatives of the series of matrix H=A*[r1,r2,t]; where A is a 3 by 3 matrix,and r1,r2,t is 3 by 1 column . During the derivatives process, A ,r1,r2,t should be viewed as the variables separately. Is anyone know how to tackle it with matlab? Or just give me some tips on this.Thank you very much!
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Andrew Newell
Andrew Newell am 18 Nov. 2011
You want partial derivatives with respect to the matrix A? That doesn't make sense.
LIU WEIHUA
LIU WEIHUA am 20 Nov. 2011
sorry ,I express wrong ,it's derivatives instead of partial derivatives.

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Antworten (1)

Alex
Alex am 20 Nov. 2011
If I understand correctly, you have H as a function of r1, r2, & t.
By this, you have 3 partial derivatives, dH/dr1, dH/dr2, & dH/dt.
If those 3 partial derivative are what you want, then this is done much easier on paper.
let, A be a matrix with elements aij, with i being the row and j be the column.
(in this case, I am assuming the matrix A has only constants, folling the same steps will get you the results for variables with higher powers).
Then, H is a system of 3 equations with 3 unknowns. Looking at the first row,
a11*r1 + a12*r2 + a13*t = H1,
then dH/dr1 becomes d(a11*r1) = dH1/dr1
then dH/dr2 becomes d(a12*r2) = dH1/dr2
then dH/dt becomes d(a13*t) = dH1/dt
(the other 2 rows follow the same).
These 9 results can be combined back into a dH matrix, with each row representing one of the partial derivatives.
  1 Kommentar
Alex
Alex am 20 Nov. 2011
This can be explained more in depth at: http://en.wikipedia.org/wiki/Matrix_calculus

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