Problem in numerical integration

1 Ansicht (letzte 30 Tage)
Habib
Habib am 1 Mai 2015
Hi every one.
I want to by means of "Trapz" do numerical integration but when I plot the result data, its shape is not what I want. in my code, u1 is my function that I wanted to do integration of it. I do double integration, first is based on y1 and second is base on x1. If u1 is plotted, it is not same of u2 shape. I couldn't detect codes defect. so, who can help me?
close all
clear all
clc
N=100;
x1=linspace(-1,1,N);
y1=x1;
z=0.42;
lambda=1030e-9;
k=2*pi/lambda;
w0=0.1;
zr=pi*w0.^2/lambda;
R=z*(1+(zr/z).^2);
w=w0*sqrt(1+(z/zr)^2);
[x,y]=meshgrid(linspace(-1,1,N));
[x2,y2]=meshgrid(linspace(-1,1,N));
r=sqrt(x.^2+y.^2);
teta=atan(y./x);
r1=sqrt(x2.^2+y2.^2);
teta1=atan(y2./x2);
u1=ones(N,N);
u=u1;
u_2=u;
u2=u;
B=u;
for i=1:N
for j=1:N
u(i,j)=(r(i,j)/w).*exp(-(r(i,j)/w).^2);
B(i,j)=besselj(1,-k.*r(i,j).*r1(i,j)./z);
u1(i,j)=r(i,j).*u(i,j).*exp(-1i*k*(r(i,j)./w).^2./(2*z)).*B(i,j);
end
end
for i=1:N
for j=1:N
u_2(:,j)=trapz(y1,u1(:,j));
end
u2(i,:)=cos(teta1(i,j)).*(-k/z).*exp(-1i*k.*(r1(i,:)./w).^2./(2*z)).*trapz(x1,u_2(i,:));%
end

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