Filter löschen
Filter löschen

How to use a matrix element to define a changing variable

7 Ansichten (letzte 30 Tage)
Kitt
Kitt am 16 Apr. 2024
Kommentiert: Kitt am 17 Apr. 2024
So I'm writing a stochastic dynamic program on decision-making based on two informational states about 2 patches to forage in. So the observer can watch a demonstrator and update an informational state on the quality of a patch. The probability of going to patch 1, p, is based on the difference between the info state of patch 1 and info state of patch 2, which changes with every time step. How do I make sure that it's calling the right numbers to compare?
The probability of going to a patch is dependent on an element in a matrix that I've made (i.e. info on patch 1<patch 2 go to patch 1 with 10%prob, info on patch 1>patch 2 go to patch 1 with 90%prob, info on patch 1=patch 2 go to patch 1 with 50%prob)
I have a matrix full of the differences between all possible values and I'm trying to use a specific element of the matrix to give this 'p' variable a value. I'm basically trying to write "if the element of matrix M, depending on the current value of z and y (that are modified by an equation), is greater than 0, then p = 0.9"
Does this make sense? p is dependent on the matrix element, but the matrix element depends on the specific fitness equation chunk it's being used for
for tt=19:-1:1
for j=1:15
for k=1:15
for i=info
if M(j,k)>0
p(j,k)==0.9;
elseif M(j,k)<0
p(j,k)==0.1;
elseif M(j,k)==0
p(j,k)==0.5;
end
Fd(i,j,k)= b*(...
m1*(...
p(y(j),z1(k))*(n1*Fd(xp(:,i),zp(j),y(k),tt+1) + (1-n1)*Fd(xpp(:,i),zpp(j),y(k),tt+1))+...

Akzeptierte Antwort

Catalytic
Catalytic am 17 Apr. 2024
Bearbeitet: Catalytic am 17 Apr. 2024
Use a single '=' sign for assigning values, not '=='.
if M(j,k)>0
p(j,k)=0.9;
elseif M(j,k)<0
p(j,k)=0.1;
elseif M(j,k)==0
p(j,k)=0.5;
end
  1 Kommentar
Kitt
Kitt am 17 Apr. 2024
Thank you! I've definitely messed that up before. Onto the next error!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by