Efficient Vectorization of For Loop

2 Ansichten (letzte 30 Tage)
Shreyas Bharadwaj
Shreyas Bharadwaj am 15 Apr. 2024
Hi,
I have three matrices and C and am trying to compute a fourth matrix Min the following way:
for p = 1:N
for q = 1:N
M(p,q) = 2 * sum(A(:,q) .* conj(B(:,p)) .* C(:,q));
end
end
All matrices are . I am trying to compute this for N = 750 or so and the computation is extremely slow. I cannot find any obvious way to vectorize the code. Any help would be very much appreciated.
Thanks.

Akzeptierte Antwort

Bruno Luong
Bruno Luong am 15 Apr. 2024
Bearbeitet: Bruno Luong am 15 Apr. 2024
Not tested but the sign reading tell me
M = 2*B' * (A.*C);
  4 Kommentare
James Tursa
James Tursa am 15 Apr. 2024
Bearbeitet: James Tursa am 15 Apr. 2024
I would guess that having 2*B' at the front will force MATLAB to physically compute the conjugate transpose of B first. However, if you segregate the 2* operation as 2 * (B' * (A.*C)), the B' would not need to be physically formed to do the conjugate transpose matrix multiply since this will be handled by flags passed into the BLAS routine. Maybe a bit faster? E.g.,
A = rand(5000); B = rand(5000); C = rand(5000);
timeit(@()2*B' * (A.*C))
ans = 0.5515
timeit(@()2*(B' * (A.*C)))
ans = 0.4901
Shreyas Bharadwaj
Shreyas Bharadwaj am 16 Apr. 2024
Thank you!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by