Simple For Loop To Find Indices
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Melissa
am 20 Apr. 2015
Bearbeitet: Guillaume
am 20 Apr. 2015
Hello.
I have a question about a simple for loop. I have an original latlon set of about 500x1 unique coordinates. I have a subset of that latlon set in which I would like to find the indices for. So I have created a for loop to try to find it.
indices = zeros(length(subset),1); %create matrix of zeros to fill
for ii=1:length(subset);
indices(ii) = find(original==subset(ii));
end
But I keep getting: Subscripted assignment dimension mismatch. What am I doing wrong? In the end I want a matrix the size of the subset to indicate which indices are correlated to my latlon subset in relation to my original latlon.
Thank you,
Melissa
0 Kommentare
Akzeptierte Antwort
Guillaume
am 20 Apr. 2015
Bearbeitet: Guillaume
am 20 Apr. 2015
The only way you can get this error with the code you've presented is if is find returns strictly less or more than one element, that is either the element of your subset is not found, or it is found more than once (i.e. your original array is not unique).
In any case, the loop is not needed there are set functions already present in matlab to do what you want. In your case, it's simply:
[~, indices] = ismember(subset, original)
0 Kommentare
Weitere Antworten (1)
Hikaru
am 20 Apr. 2015
Bearbeitet: Hikaru
am 20 Apr. 2015
Are your variables stored as double, or cells?
edit: I'm sorry. I made a mistake and I removed the incorrect statement.
2 Kommentare
Hikaru
am 20 Apr. 2015
I tried your code using a smaller sized variables,
original = [60; 40; 100; 120];
subset = [120; 40; 60];
indices = zeros(length(subset),1);
for ii=1:length(subset);
indices(ii) = find(original==subset(ii))
end
and it works okay as long as the values in subset can also be found in the original vector.
I'm not sure why you got that error without looking at the sample matrix, but have you check if there are same values in the original vector?
Siehe auch
Kategorien
Mehr zu Logical finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!