3D indices for particular values in a 3D array

2 Ansichten (letzte 30 Tage)
William Sherwin
William Sherwin am 8 Apr. 2024
Kommentiert: Stephen23 am 9 Apr. 2024
I want to find the 3D indices for particular values in a 3D array. I was expecting to use something like one would use for a 2D array:
>>[row,col] = find(a==8)
So I tried
>>[row,col,page] = find(a==8)
and
>>[row,col,sheet] = find(a==8)
but these just gave nonsense. Surely there is a way to do this?
W.Sherwin@unsw.edu.au

Akzeptierte Antwort

Stephen23
Stephen23 am 8 Apr. 2024
Bearbeitet: Stephen23 am 8 Apr. 2024
Use IND2SUB:
X = randi(9,4,3,2)
X =
X(:,:,1) = 9 4 1 3 1 8 5 3 7 8 8 4 X(:,:,2) = 7 4 7 7 9 3 6 3 9 8 2 7
[R,C,P] = ind2sub(size(X),find(X==8))
R = 4x1
4 4 2 4
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
C = 4x1
1 2 3 1
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
P = 4x1
1 1 1 2
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
  2 Kommentare
William Sherwin
William Sherwin am 8 Apr. 2024
Thanks Stephen23 ! Bill Sherwin
Stephen23
Stephen23 am 9 Apr. 2024
@William Sherwin: please remember to click the accept button of the answer that helped you!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange

Produkte


Version

R2023b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by