Modifying function to get only one value
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How to modify the following function such that output values (x,y,w) come out either for:
abs((w(r2) - ((x(r1)-a(i))^2 + (y(r1)-b(i))^2)) > (w(r1) * ((x(r2)-a(i))^2 + (y(r2)-b(i))))^2)
or
abs((w(r2) - ((x(r1)-a(i))^2 + (y(r1)-b(i))^2)) < (w(r1) * ((x(r2)-a(i))^2 + (y(r2)-b(i))))^2),
the original code is mentioned below
function f = objective(vars, a, b, reg1, reg2)
x = vars(1:26);
y = vars(27:52);
w = vars(53:end);
f = 0;
for i = 1:numel(a)
r1 = reg1(i);
r2 = reg2(i);
f = f + max(0,(abs((w(r2) - ((x(r1)-a(i))^2 + (y(r1)-b(i))^2)) - (w(r1) * ((x(r2)-a(i))^2 + (y(r2)-b(i))))^2)));
end
1 Kommentar
Antworten (1)
Manikanta Aditya
am 8 Apr. 2024
Hello,
To modify the function so that it outputs values (x), (y), and (w) based on the conditions you've specified, you can incorporate an if statement as suggested by @Torsten.
The conditions you've mentioned seem to be criteria for selecting or processing specific cases rather than directly affecting the output format.
However, it's not entirely clear how you want to use these conditions to modify the output directly since the original function accumulates a scalar value 'f' based on all iterations.
function f = objective(vars, a, b, reg1, reg2)
x = vars(1:26);
y = vars(27:52);
w = vars(53:end);
f = 0;
for i = 1:numel(a)
r1 = reg1(i);
r2 = reg2(i);
condition1 = abs((w(r2) - ((x(r1)-a(i))^2 + (y(r1)-b(i))^2)) > (w(r1) * ((x(r2)-a(i))^2 + (y(r2)-b(i))^2))^2);
condition2 = abs((w(r2) - ((x(r1)-a(i))^2 + (y(r1)-b(i))^2)) < (w(r1) * ((x(r2)-a(i))^2 + (y(r2)-b(i))^2))^2);
if condition1 || condition2
% Modify this part as needed based on how you want to use the conditions
f = f + max(0, (abs((w(r2) - ((x(r1)-a(i))^2 + (y(r1)-b(i))^2)) - (w(r1) * ((x(r2)-a(i))^2 + (y(r2)-b(i))^2))^2)));
else
% Optionally, handle cases where neither condition is met
% For example, you could simply skip these cases or handle them differently
end
end
end
This modification checks each of the conditions you've specified (condition 1 and condition 2) and only performs the calculation and accumulation off 'f' if either of the conditions is true.
Hope this helps, Thank you.
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