Creating a loop to assign 20 players to two teams and deleting columns

Hi, I am working on a project that includes seperating 20 players to two teams: TeamA and TeamB. I have created a 3x20 matrix which includes player jerseys from 1-20, the second row is random free throw percentages from 50-90, and the third row is random average # of turnovers per game from 0-8. TeamA desires highest free throw percentage and TeamB desires lowest turnovers per game. Before each team can pick, a coin flip is done to decide which team picks each round. Both teams will recieve 10 players each. My question: is my loop correct? Here is my code so far... This is only helping me with a small part of my project, thanks.

numPlayers = 20;
ftPercent = randi([50,90],1,numPlayers);
avgNumTurnover = randi([0,8],1,numPlayers);
playerInfo = [1:1:numPlayers;ftPercent;avgNumTurnover];

coinFlip = round(rand(1,1));
% A 1 from the coinFlip is a heads
% A 0 from the coinFlip is a tails
for i = 1:numPlayers

if coinFlip == 1
    TeamA = max(playerInfo(:,2))

else 
    TeamB = min(playerInfo(3,:))
end
end

Answer 1

[Walter Roberson]

numPlayers = 20;
ftPercent = randi([50,90],1,numPlayers);
avgNumTurnover = randi([0,8],1,numPlayers);
playerInfo = [1:1:numPlayers;ftPercent;avgNumTurnover];

TeamA = [];
TeamB = [];
coinFlip = round(rand(1,1));
% A 1 from the coinFlip is a heads
% A 0 from the coinFlip is a tails
for i = 1:numPlayers
    if coinFlip == 1
        [~,TeamA(end+1)] = max(playerInfo(:,2));
        playerInfo(TeamA(end),2:3) = 0;
    else 
        [~,TeamB(end+1)] = min(playerInfo(3,:));
        playerInfo(TeamB(end),2:3) = 0;
    end
end

Your coinflip logic is definitely wrong though... You currently have arranged so that if the coinFlip is 1 then teamA gets all 20 players, and otherwise TeamB gets all 20 players.