How to obtain all permutations of multiple cell arrays?
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I have a few cell arrays of character vectors - let's say 3 in this case - A, B, C.
A={'a1'; 'a2'; 'a3'};
B={'b1'; 'b2'};
C={'c1'; 'c2'; 'c3'; 'c4'};
I wish to find all permutations of elements of A, B, and C. That is, one element from each. Such as:
{'a1', 'b1', 'c1'; 'a1', 'c1', 'b1'; 'b1', 'a1', 'c1'; 'a1', 'b1', 'c2'; .... }
Please note that I am not looking for only combinations - I believe that would have been easily addressed by:
X=combinations(A, B, C);
I am also not looking for permutations that would produce combinations/permutations of elements from within one of the cell arrays above - so that I couldn't just do:
X=vertcat(A,B,C);
perms(X);
Is there an efficient way to do this without all sorts of loops?
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Akzeptierte Antwort
Matt J
am 17 Mär. 2024
Bearbeitet: Matt J
am 17 Mär. 2024
This is better because the for loop is only 6 iterations long.
A={'a1'; 'a2'; 'a3'};
B={'b1'; 'b2'};
C={'c1'; 'c2'; 'c3'; 'c4'};
p=perms(1:3);
c= combinations(C,B,A);
N=height(p)
Z=cell(N,1);
for i=1:N
Z{i}=c(:,p(i,:));
end
Z=vertcat(Z{:})
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Weitere Antworten (2)
Matt J
am 17 Mär. 2024
Bearbeitet: Matt J
am 17 Mär. 2024
Using this FEX download,
c= table2cell(combinations(C,B,A));
result = blkColon( c(:,perms(1:3)') , [1,3])
result =
144×3 cell array
{'a1'} {'b1'} {'c1'}
{'a2'} {'b1'} {'c1'}
{'a3'} {'b1'} {'c1'}
{'a1'} {'b2'} {'c1'}
{'a2'} {'b2'} {'c1'}
{'a3'} {'b2'} {'c1'}
{'a1'} {'b1'} {'c2'}
{'a2'} {'b1'} {'c2'}
{'a3'} {'b1'} {'c2'}
{'a1'} {'b2'} {'c2'}
{'a2'} {'b2'} {'c2'}
{'a3'} {'b2'} {'c2'}
{'a1'} {'b1'} {'c3'}
...
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