Using continous time in Matlab editor
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Olutayo Omotoso
am 25 Feb. 2024
Beantwortet: Olutayo Omotoso
am 28 Feb. 2024
In the code below, I need to use continous time to generate phi. I want to achieve this in MATLAB editor. I can do this in Simulink using simulink clock block. I want the time t in the editor's script to emulate the clock's block time. Kindly help.
V1 = 18; % Input voltage
R = 7.2; % Load resistance
a = 0 * (2*pi/360); % pulse shift angle (rad)
fs = 70000; % Switching frequency
phi = pi* ((31*2/360) - (0.028*sin(2*pi*t)))); % Phase shift (pi.d in rad) & t is time
0 Kommentare
Akzeptierte Antwort
Walter Roberson
am 25 Feb. 2024
Pi = sym(pi);
syms t
phi = Pi * ((31*2/360) - (0.028*sin(2*Pi*t))) % Phase shift (pi.d in rad) & t is time
phi is expressed in continuous time t
I have to wonder whether your actual equation is
phi = Pi * ((31*2/360)) - (0.028*sin(2*Pi*t))
fplot(phi, [0 10])
Weitere Antworten (2)
Alexander
am 25 Feb. 2024
Maybe something simple like that:
V1 = 18; % Input voltage
R = 7.2; % Load resistance
t = 0:0.001:3*pi;
a = 0 * (2*pi/360); % pulse shift angle (rad)
fs = 70000; % Switching frequency
phi = pi* ((31*2/360) - (0.028*sin(2*pi*t))); % Phase shift (pi.d in rad) & t is time
plot(t,phi)
3 Kommentare
Alexander
am 25 Feb. 2024
If forgotten a remark. If fs is the sample frequency just replace 0.001 by 1/70000.
Siehe auch
Kategorien
Mehr zu Sources finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!