How to define a for loop for given FINDPEAKS problem ?
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YQ
am 24 Feb. 2024
Kommentiert: Dyuman Joshi
am 29 Feb. 2024
[A1,L] = findpeaks(A(:,1));
A1(:,2) = A(L,2);
[A2,L1] = findpeaks(A1(:,1));
A2(:,2) = A1(L1,2);
[A3,L2] = findpeaks(A2(:,1));
A3(:,2) = A2(L2,2);
2 Kommentare
Dyuman Joshi
am 24 Feb. 2024
Bearbeitet: Dyuman Joshi
am 24 Feb. 2024
What exactly are you trying to do here?
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Dyuman Joshi
am 24 Feb. 2024
Try this -
n=3;
B = [num2cell(A,1); cell(n,2)]
for k=2:n
[B{k,1}, L] = findpeaks(B{k-1,1});
B{k,2} = B{k-1,2}(L);
end
Here 1st row of B corresponds to A, 2nd to A1, 3rd to A2 and 4th to A3.
Use indexing to access the data.
7 Kommentare
Dyuman Joshi
am 29 Feb. 2024
Ah, that's a typo. My bad.
To correct it, replace
num = numel(d);
with
num = numel(data);
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