How can I define vector p without using function statement?
suppose
t = 0:0.1:1
p = sin(t) when t<0.6
p = 0 when t>=0.6

2 Kommentare

DGM
DGM am 23 Feb. 2024
Bearbeitet: DGM am 23 Feb. 2024
What's wrong with just
t = 0:0.1:1;
p = sin(t).*(t<0.6);
plot(t,p)
... of course, the range and resolution of t makes this plot appear a bit unclear.
fumio hakamada
fumio hakamada am 23 Feb. 2024
Thank you for your reply.

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 Akzeptierte Antwort

Rik
Rik am 23 Feb. 2024

0 Stimmen

I don't know if you want to avoid anonymous functions as well, but this should give you a finer plot:
% p = sin(t) when t<0.6
% p = 0 when t>=0.6
p = @(t) (t<0.6).*sin(t);
fplot(p,[0 1])
The problem here is mostly that sin(x) is very close to x for small x, which means you have a fairly straight line. Adding a straight line helps to show there is actually a slight curve:
p = @(t) (t<0.6).*sin(t);
figure
fplot(p,[0 1])
hold on
fplot(@(t) sign(p(t)).*t,[0 1])
legend({'y = sin(t)','y = x'})

2 Kommentare

fumio hakamada
fumio hakamada am 23 Feb. 2024
Verschoben: Rik am 23 Feb. 2024
I had no idea about logical vector and usage of ".*". Thanks for both of you.
Rik
Rik am 23 Feb. 2024
You're welcome. If my answer solved your issue, please consider marking it as accepted.

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am 23 Feb. 2024

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Rik
am 23 Feb. 2024

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