plot() and fplot() give different results for the same function

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I'm trying to plot the function
between 0 and 100 (not including zero of course), but am running into a problem. When I use
x = linspace(0, 100, 10000);
y = 2.*sqrt(1+x)+((sin(sqrt(x).*pi).*sin(sqrt(1+x).*pi).*(2.*x+1))/(sqrt(x))) - 2.*sqrt(1+x).*cos(sqrt(x).*pi).*cos(sqrt(1+x).*pi);
plot(x,y);
I don't get the result I expected, which is the graph occasionally intersecting y = 0. However, by doing
fplot(@(x) 2.*sqrt(1+x)+((sin(sqrt(x).*pi).*sin(sqrt(1+x).*pi).*(2.*x+1))/(sqrt(x))) - 2.*sqrt(1+x).*cos(sqrt(x).*pi).*cos(sqrt(1+x).*pi), [0 100]);
I do get the result I expected.
I can't just use fplot, as I do need to use the variable y for other things, so I'm not sure what to do or what is even happening here. Any help would be greatly appreciated.

Akzeptierte Antwort

Bruno Luong
Bruno Luong am 15 Feb. 2024
Bearbeitet: Bruno Luong am 15 Feb. 2024
Your coding is wrong: Replace "/" with "./"

Weitere Antworten (1)

Torsten
Torsten am 15 Feb. 2024
Bearbeitet: Torsten am 15 Feb. 2024
x = linspace(0, 100, 10000);
y = 2*sqrt(1+x)+sin(sqrt(pi)*x).*sin(sqrt(1+x)*pi).*(2*x+1)./sqrt(x) - 2*sqrt(1+x).*cos(sqrt(x)*pi).*cos(sqrt(1+x)*pi);
plot(x,y);
hold on
f = @(x)2*sqrt(1+x)+sin(sqrt(pi)*x).*sin(sqrt(1+x)*pi).*(2*x+1)./sqrt(x) - 2*sqrt(1+x).*cos(sqrt(x)*pi).*cos(sqrt(1+x)*pi);
fplot(f,[0 100])
  1 Kommentar
Bruno Luong
Bruno Luong am 15 Feb. 2024
Bearbeitet: Bruno Luong am 15 Feb. 2024
I believe fplot ezplot replace "*" "/" "^" etc... with elementwise operators ".*" "./', ".^". It interprets as standard math notation.
This how charming or quirking MATLAB is, depending on your taste.

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