# Unable to comprehend "time" function output

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VBBV am 9 Feb. 2024
Bearbeitet: Stephen23 am 9 Feb. 2024
d = caldays(8:10) + hours(1.2345)
d = 1×3 calendarDuration array
8d 1h 14m 4.2s 9d 1h 14m 4.2s 10d 1h 14m 4.2s
t = time(d) % this output
t = 1×3 duration array
01:14:04 01:14:04 01:14:04
Is this output returning the difference between time components of calenderDuration function or only time duration between time values in the array ? can anyone tell more about this output
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### Akzeptierte Antwort

Stephen23 am 9 Feb. 2024
Bearbeitet: Stephen23 am 9 Feb. 2024
"Is this output returning the difference between time components of calenderDuration function or only time duration between time values in the array "
Neither, there are absolutely no differences involved.
Exactly as the TIME documentation states, it returns the time component of calendar duration objects.
In pseudo-nomenclature, if you have this CALENDARDURATION array:
99 days 12h 34m 56s789
then TIME returns the time part only (as a DURATION array):
12h 34m 56s789
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Stephen23 am 9 Feb. 2024
If differences were involved this would not work:
d = caldays(8) + hours(1.2345)
d = calendarDuration
8d 1h 14m 4.2s
t = time(d)
t = duration
01:14:04
t.Format = "hh:mm:ss.SSS"
t = duration
01:14:04.200
VBBV am 9 Feb. 2024
Ok, Thanks for explanation @Stephen23

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