How to do this below?

Suppose you have a binary sequence:

a = [0 0 1 1 1 0 0 1 1 1 1 0 0 0];

And, how can you abtain a sequence b from a?

b = [0 0 3 0 0 0 0 4 0 0 0 0 0 0];

That is, place the sum of the consequtive ones at the first location of the consecutive ones.

And, make zeros for all the other locations of ones.

Thank you,

Answer 1

[Voss]

One way:

a = [0 0 1 1 1 0 0 1 1 1 1 0 0 0]

a = 1x14

0 0 1 1 1 0 0 1 1 1 1 0 0 0

b = zeros(1,numel(a));
s_idx = strfind([0 a],[0 1]);
e_idx = strfind([a 0],[1 0]);
b(s_idx) = e_idx-s_idx+1;

b

b = 1x14

0 0 3 0 0 0 0 4 0 0 0 0 0 0

[Mibang]

Genius! thanks.

[Voss]

You're welcome!