Minimum value from a vector for x in the range: x= [-4:0.5:4]; Calculate f(x)=x2+1.3x+2.

How to solve this?

[Ramesh]

For x in the range: x= [-4:0.5:4];

Calculate f(x)=x2+1.3x+2.

Report the minimum value in the above vector generated in MATLAB, as well as the value of x at which f(x) is minimum.

Please report the minimum value of the f(x) vector obtained

Please report the value in the vector x at which this minimum is obtained

[VBBV]

use the function min and find the index at which this occurs in vector x

[Sam Chak]

Hi @Ramesh, does the visual help you to understand?

x = -2:0.5:2

x = 1×9

-2.0000 -1.5000 -1.0000 -0.5000 0 0.5000 1.0000 1.5000 2.0000

f = x.^2 + 1.3*x + 2

f = 1×9

3.4000 2.3000 1.7000 1.6000 2.0000 2.9000 4.3000 6.2000 8.6000

plot(x, f, '-o'), grid on, xlabel x, ylabel f(x)

Answer 1

[VBBV]

x = -4:0.5:4;
f = @(x) x.^2 + 1.3*x + 2

f = function_handle with value:
    @(x)x.^2+1.3*x+2

[F idx] = min(f(x))

F = 1.6000

idx = 8

xv = x(idx)  % value of x at which minimum of f(x) occurs

xv = -0.5000