how to split principal vector "a" into sub vectors a1, a2, a3 and a4
exemple:
a=[1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39];
a1=[1 3 5 8];
a2=[11 12 15 17 18 19 20];
a3=[21 24 29];
a4=[31 32 33 34 35 36 38 39];
thnkx

3 Kommentare

Stephen23
Stephen23 am 30 Jan. 2024
Bearbeitet: Stephen23 am 30 Jan. 2024
What is the rule for splitting into those vectors?
For example:
  • why is 20 in a2 and not in a3 ?
  • why is 21 in a3 and not in a2 ?
Note that creating numbered variables is not a good approach. Much better to use a cell array.
benghenia aek
benghenia aek am 30 Jan. 2024
I want to split the big array "a" into:
a1 "the numbers between 0 and 10"
a2 "the numbers between 11 and 20"
a3 "the numbers between 21 and 30"
and make it into cell arrays
Dyuman Joshi
Dyuman Joshi am 19 Feb. 2024
Any updates, @benghenia aek?

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 Akzeptierte Antwort

Dyuman Joshi
Dyuman Joshi am 30 Jan. 2024
Bearbeitet: Dyuman Joshi am 19 Feb. 2024

0 Stimmen

a = [1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39 69].';
%bin the data into groups of 10
k = findgroups(floor((a-1)/10));
z = accumarray(k, a, [], @(x) {x.'})
z = 5×1 cell array
{[ 1 3 5 8]} {[ 11 12 15 17 18 19 20]} {[ 21 24 29]} {[31 32 33 34 35 36 38 39]} {[ 69]}

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Matt J
Matt J am 30 Jan. 2024
Bearbeitet: Matt J am 19 Feb. 2024

0 Stimmen

a = [1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39];
G=findgroups(discretize(a,[0:10:max(a)+10],'Include','right'));
z=splitapply(@(x){x}, a, G)
z = 1x4 cell array
{[1 3 5 8]} {[11 12 15 17 18 19 20]} {[21 24 29]} {[31 32 33 34 35 36 38 39]}

2 Kommentare

splitapply() won't work if there is a gap in the data -
a = [1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39 69];
G=discretize(a,[0:10:max(a)+10],'Include','right');
z=splitapply(@(x){x}, a, G)
Error using splitapply
For N groups, every integer between 1 and N must occur at least once in the vector of group numbers.
Small modification,
a = [1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39 69];
G=findgroups(discretize(a,[0:10:max(a)+10],'Include','right'));
z=splitapply(@(x){x}, a, G)
z = 1x5 cell array
{[1 3 5 8]} {[11 12 15 17 18 19 20]} {[21 24 29]} {[31 32 33 34 35 36 38 39]} {[69]}

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