Generating a rather intricate loop with inequalities

I have to create a code that, given positive integers m and n, calculates integers k and r such that m=kn+r and r<n by successively subtracting n first from m and then from m-n and then from m-2n and so on in a loop. as many times as possible without the remainder r=m-kn becoming negative, and which finally prints k and r on the screen.

This seems a little confusing, since r and k are not calculated readily, since we have an inequality at r<n, and not an equality. If it was r=n, we would have no problem and could proceed to the loop.

My code is as given, however, it stops since r<n and cannot be calculated. Any ideas how to solve this? Thanks

m=1
n=2
% Initialize the starting number
number = m;
% Loop 
while number <= m-n*n
    disp(number);
    number = number-n;  % Subtract n from m
end
if r==m-kn;
end
if r<n;
end

Answer 1

[Hassaan]

Your current code does not correctly calculate k and r. Here's an adjusted version:

m = 1;  % Example values for m
n = 2;  % Example values for n

% Initialize k and r
k = 0;
r = m;

% Loop to find k and r
while r >= n
    r = r - n;  % Subtract n from r
    k = k + 1;  % Increase k by 1 for each subtraction
end

% Display the results
fprintf('k: %d, r: %d\n', k, r);

k: 0, r: 1

This code initializes k and r, then uses a loop to subtract n from r until r is less than n. Each subtraction increases k by 1. After the loop, k and r will satisfy the conditions m = kn + r and r < n.

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[Sergio]

Thanks Muhammad, but why did you set k=0?