How to perform minimization with fminsearch and fmincon

3 Ansichten (letzte 30 Tage)
Akhil
Akhil am 17 Jan. 2024
Bearbeitet: Walter Roberson am 17 Jan. 2024
syms x [1 26]
syms y [1 26]
syms w [1 26]
f = 0;
for i = 1:numel(a)
r1 = reg1(i);
r2 = reg2(i);
f = f + w(r2) * sqrt((x(r1)-a(i))^2 + (y(r1)-b(i))^2) - w(r1) * sqrt((x(r2)-a(i))^2 + (y(r2)-b(i))^2);
end
expr_func = matlabFunction(f, 'Vars', {[x, y, w]});
In the above code, i want to perform minimzation using fmin search. Also, how to ensure that f = f + w(r2) * sqrt((x(r1)-a(i))^2 + (y(r1)-b(i))^2) - w(r1) * sqrt((x(r2)-a(i))^2 + (y(r2)-b(i))^2) >=0

Antworten (1)

Walter Roberson
Walter Roberson am 17 Jan. 2024
%guesses for initial conditions
x0 = linspace(-1,1,26);
y0 = linspace(-2,2,26);
w0 = linspace(-3,3,26);
xyw0 = [x0, y0, w0];
%the search
bestxyw = fminsearch(expr_fun, xyw0);
bestx = bestxyw(1:26);
besty = bestxyw(27:52);
bestw = bestxyw(53:78);
  1 Kommentar
Walter Roberson
Walter Roberson am 17 Jan. 2024
Bearbeitet: Walter Roberson am 17 Jan. 2024
Ensuring that the partial expressions are >= 0.
This can be done with fmincon but not with fminsearch.
syms x [1 26]
syms y [1 26]
syms w [1 26]
sym parts [26 1]
f = sym(0);
for i = 1:numel(a)
r1 = reg1(i);
r2 = reg2(i);
partial = w(r2) * sqrt((x(r1)-a(i))^2 + (y(r1)-b(i))^2) - w(r1) * sqrt((x(r2)-a(i))^2 + (y(r2)-b(i))^2);
parts(i) = partial;
f = f + partial;
end
expr_func = matlabFunction(f, 'Vars', {[x, y, w]});
part_func = matlabFunction(-parts, 'Vars', {[x, y, w]});
A = []; b = [];
Aeq = []; beq = [];
lb = []; ub = [];
nonlcon = part_func;
%guesses for initial conditions
x0 = linspace(-1,1,26);
y0 = linspace(-2,2,26);
w0 = linspace(-3,3,26);
xyw0 = [x0, y0, w0];
%the search
bestxyw = fmincon(expr_fun, xyw0, A, b, Aeq, beq, lb, ub, nonlcon);
bestx = bestxyw(1:26);
besty = bestxyw(27:52);
bestw = bestxyw(53:78);

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Optimization finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by