Hello everyone, I have a huge ascii.txt wind file with the following format.
time = 0 hour
2 3 4 5 6 7
0 9 8 7 6 5
7 6 5 4 3 2
9 8 7 6 5 4
time = 3 hour
2 3 4 5 6 7
0 9 8 7 6 5
7 6 5 4 3 2
9 8 7 6 5 4
The thing is that I need to flip the rows from each block between hours, like this
time = 0 hour
9 8 7 6 5 4
7 6 5 4 3 2
0 9 8 7 6 5
2 3 4 5 6 7
time = 3 hour
9 8 7 6 5 4
7 6 5 4 3 2
0 9 8 7 6 5
2 3 4 5 6 7
I can do this for one block by
X = readlines('xwind.txt');
Y = X(2:5);
Y = flip(Y);
But I couldn’t write the loop for the entire file (4865x1 string).
Any help would be much appreciated.

 Akzeptierte Antwort

Dyuman Joshi
Dyuman Joshi am 11 Dez. 2023

0 Stimmen

If the format of the data is homogenous through the file, try this -
in = readlines('ascii.txt')
in = 10×1 string array
"time = 0 hour" "2 3 4 5 6 7 " "0 9 8 7 6 5" "7 6 5 4 3 2" "9 8 7 6 5 4" "time = 3 hour" "2 3 4 5 6 7 " "0 9 8 7 6 5" "7 6 5 4 3 2" "9 8 7 6 5 4"
for k=2:5:size(in,1)
in(k:k+3,:) = flipud(in(k:k+3,:));
end
in
in = 10×1 string array
"time = 0 hour" "9 8 7 6 5 4" "7 6 5 4 3 2" "0 9 8 7 6 5" "2 3 4 5 6 7 " "time = 3 hour" "9 8 7 6 5 4" "7 6 5 4 3 2" "0 9 8 7 6 5" "2 3 4 5 6 7 "

2 Kommentare

gero pulido
gero pulido am 12 Dez. 2023
Thank you! It worked perfectly
Dyuman Joshi
Dyuman Joshi am 12 Dez. 2023
You're welcome!

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Weitere Antworten (1)

Mathieu NOE
Mathieu NOE am 11 Dez. 2023

0 Stimmen

hello
try this
I choosed to store each Y array into a cell
D=readlines('data.txt'); % read as string array
[eof] = size(D,1); % last row number (end of file)
ixP1=find(contains(D,'time')); % find the "time" line
ixP1=[ixP1 ; eof]; % add end of file line number
for k=1:numel(ixP1)-1
ind = ixP1(k)+1:ixP1(k+1)-1;
Y = str2num(char(D(ind)));
Y = flip(Y);
out{k} = Y; % store Y flipped in cell array
end

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