Hello I am going to put a time-varying ohmic load at the output of an inverter. How can I do this so that its value decreases from 15 ohms to 10 ohms at time t=2s?

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atharva
atharva am 7 Dez. 2023

0 Stimmen

Hey Reza,
I understand that you want to put a time-varying ohmic load at the output of an inverter so that it's value decrease from 15 ohms to 10 ohms at time t=2s.
You can create a time-varying ohmic load by defining a function that returns the resistance value at each time step. Here's an example code snippet that creates a load that decreases from 15 ohms to 10 ohms at t=2s:
function R = load_func(t)
if t < 2
R = 15 - 2.5*t;
else
R = 10;
end
end
You can then use this function in your simulation by calling it at each time step and using the returned value as the load resistance.
I hope this helps!

1 Kommentar

reza hakimi
reza hakimi am 9 Dez. 2023
Hello Thank you for your reply This function that you defined is directly connected to the output of the inverter Or it is given to a variable resistor

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