How can draw this kind of graph?
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how can we draw a velocity profile of the 3rd-order non-linear boundary value problem that converges for different values? give me code for u'''+u*u''+s*[Gr*G+Gm*H-M*u']=0 where s=0.02, Gm=10, Gr=4 and M=0.1 with boundary condition u=1,u'=0.001; G=0.001; H=0.001 when t=0 and u'=0; G-0; H=0 when t= infinity, where H=2 and G=4 within one graph for Different values of Gm
6 Kommentare
Rik
am 13 Nov. 2023
You can attempt a first try with the new ChatGPT-powered AI playground if you have trouble figuring out the first steps.
gkb
am 13 Nov. 2023
gkb
am 13 Nov. 2023
Torsten
am 13 Nov. 2023
Use bvp4c or bvp5c to set up the problem.
Sam Chak
am 13 Nov. 2023
@gkb, I'm confused.
You only introduced ONE differential equation in the question.
where the parameters other than the state variables u,
,
, are constants.
Why do F, G, and H magically appear in the context? Can we settle the
first and then post another question for the system of differential equations F, G, H?
Antworten (1)
Syed Sohaib Zafar
am 19 Nov. 2023
Bearbeitet: DGM
am 20 Nov. 2023
Here's your required code
code_gkb_Matlab
%%%%%%%%%%%%%%%
function code_gkb_Matlab
global eps Gr Gm M Pr Jh Sc S0
%eq1
eps=0.001; Gr=0.5; M=0.5;
% eq2
Pr=1.4; Jh=0.3; %eps M
% eq3
Sc=0.7; S0=0.2;
val=[0.1 0.2 0.3 0.4];
for i = 1:1:4;
Gm = val(i);
solinit = bvpinit(linspace(0,6),[0 1 0 1 0 1 0]);
sol= bvp4c(@shootode,@shootbc,solinit);
eta = sol.x;
f = sol.y;
figure (1)
plot(eta,f(2,:));
xlabel( '\eta');
ylabel('\bf f'' (\eta)');
hold on
end
lgd=legend('Gm = 0.1','Gm = 0.2','Gm = 0.3','Gm = 0.4');
end
function dydx = shootode(eta,f);
global eps Gr Gm M Pr Jh Sc S0
dydx = [f(2)
f(3)
-f(1)*f(3)-eps*(Gr*f(4)+Gm*f(6)-M*f(2))
f(5)
-Pr*f(1)*f(5)+Jh*Pr*((1/eps)*f(3)^2+M*f(2)^2)
f(7)
2*Sc*f(2)*f(6)-Sc*f(1)*f(7)-S0*Sc*(-Pr*f(1)*f(5)+Jh*Pr*((1/eps)*f(3)^2+M*f(2)^2))
];
end
function res = shootbc(fa,fb)
global eps
res = [fa(1)-1; fa(2)-eps; fa(4)-eps; fa(6)-eps; fb(2)-0; fb(4)-0; fb(6)-0];
end
1 Kommentar
DGM
am 20 Nov. 2023
Edited to add formatting and to make it run.
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