i want to find k for different values of w using determinants, after that i want to find y2 for the different values but y2 cannot be executed
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Rosalinda
am 9 Nov. 2023
Verschoben: Steven Lord
am 9 Nov. 2023
%finding k for different values of w
syms k
c44=44;
i=sqrt(-1);
w=1:3;
y1=zeros(1,length(w));
s=sym(zeros(1,length(w)));
p=sym(zeros(1,length(w)));
q=sym(zeros(1,length(w)));
y=sym(zeros(1,length(w)));
for j=1:length(w)
s(j)=c44*exp(k)*w(j);
p(j)=c44/w(j);
q(j)=c44+w(j)*i/k^2;
A=[c44*s(j) 2;p(j) q(j)];
z=det(A);
y(j)=vpasolve(z,k);
disp(y)
y1=real(y);
%relation between y1(or value of k) and w
y2(j)=w/y1(j);
end
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Steven Lord
am 9 Nov. 2023
w is a vector.
w=1:3
y1(j) is a scalar. For purposes of this example I'll show a "dummy" y1 vector.
y1 = [4 5 6];
j = 1;
y1(j)
What do you get when you divide w by y1(j)? What size is that result?
result = w/y1(j)
y2(j) is also a scalar (a 1-by-1 array.)
Can you stuff a 1-by-3 vector into a 1-by-1 array? To use a metaphor, can you fit three eggs into the same cup of an egg carton (without scrambling them)? No, you can't. So MATLAB throws an error when you try.
Perhaps you meant to divide w(j) by y1(j)?
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