Delete rows of excel if any empty cell found

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Adi Purwandana
Adi Purwandana am 13 Okt. 2023
Bearbeitet: Adi Purwandana am 15 Okt. 2023
Dear everyone,
I have an excel file containing some Stations defined in the first column (attached). Here, as shown below, I have 4 stations. Some stations contain no value (empty cell) like Station 1; and some stations not all cells have values.
Does anyone know how to delete the row if there's any cell with no value detected? In this case, there will be 3 stations left and the rows with empty cells in those 3 stations will be omited :
best regards
  3 Kommentare
Walter Roberson
Walter Roberson am 13 Okt. 2023
I do not see any height information in that table?
If you are trying to sort by depth see sortrows
Adi Purwandana
Adi Purwandana am 13 Okt. 2023
Bearbeitet: Adi Purwandana am 13 Okt. 2023
Thank you for your response @Walter Roberson. Here is what I want:
Attached file is the excel file. So, it must be ordered from the shorter (shallower) station to the longer one and so on... Any suggestions? I tried using sortrows but it doesn't solve.

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Star Strider
Star Strider am 13 Okt. 2023
I am not certain how you want to sort the ‘Station’ by ‘shortest to the longest’.
Try this —
T1 = readtable('datax.xlsx', 'VariableNamingRule','preserve')
T1 = 24×9 table
Station Lon Lat Depth Salinity Temperature u v yyyy-mm-ddThh:mm:ss.sss _______ ______ _____ _____ ________ ___________ _____ ______ _______________________ 1 114.8 -8.16 0 NaN NaN NaN NaN {'2023-10-08T00:00:00'} 1 114.8 -8.16 2 NaN NaN NaN NaN {'2023-10-08T00:00:00'} 1 114.8 -8.16 4 NaN NaN NaN NaN {'2023-10-08T00:00:00'} 1 114.8 -8.16 6 NaN NaN NaN NaN {'2023-10-08T00:00:00'} 1 114.8 -8.16 8 NaN NaN NaN NaN {'2023-10-08T00:00:00'} 1 114.8 -8.16 10 NaN NaN NaN NaN {'2023-10-08T00:00:00'} 2 114.88 -8.16 0 33.981 29.324 0.11 -0.017 {'2023-10-08T00:00:00'} 2 114.88 -8.16 2 33.979 29.248 0.106 -0.011 {'2023-10-08T00:00:00'} 2 114.88 -8.16 4 33.979 29.25 0.106 -0.011 {'2023-10-08T00:00:00'} 2 114.88 -8.16 6 33.978 29.251 0.105 -0.011 {'2023-10-08T00:00:00'} 2 114.88 -8.16 8 33.978 29.251 0.105 -0.011 {'2023-10-08T00:00:00'} 2 114.88 -8.16 10 NaN NaN NaN NaN {'2023-10-08T00:00:00'} 3 114.96 -8.16 0 33.995 29.171 0.109 -0.037 {'2023-10-08T00:00:00'} 3 114.96 -8.16 2 33.992 29.108 0.104 -0.03 {'2023-10-08T00:00:00'} 3 114.96 -8.16 4 33.992 29.11 0.102 -0.03 {'2023-10-08T00:00:00'} 3 114.96 -8.16 6 33.992 29.114 0.102 -0.03 {'2023-10-08T00:00:00'}
T1{:,end} = cellfun(@(x)datetime(x, 'InputFormat','yyyy-MM-dd''T''HH:mm:ss', 'Format','yyyy-MM-dd HH:mm:ss'), T1{:,end}, 'Unif',0)
T1 = 24×9 table
Station Lon Lat Depth Salinity Temperature u v yyyy-mm-ddThh:mm:ss.sss _______ ______ _____ _____ ________ ___________ _____ ______ _______________________ 1 114.8 -8.16 0 NaN NaN NaN NaN {[2023-10-08 00:00:00]} 1 114.8 -8.16 2 NaN NaN NaN NaN {[2023-10-08 00:00:00]} 1 114.8 -8.16 4 NaN NaN NaN NaN {[2023-10-08 00:00:00]} 1 114.8 -8.16 6 NaN NaN NaN NaN {[2023-10-08 00:00:00]} 1 114.8 -8.16 8 NaN NaN NaN NaN {[2023-10-08 00:00:00]} 1 114.8 -8.16 10 NaN NaN NaN NaN {[2023-10-08 00:00:00]} 2 114.88 -8.16 0 33.981 29.324 0.11 -0.017 {[2023-10-08 00:00:00]} 2 114.88 -8.16 2 33.979 29.248 0.106 -0.011 {[2023-10-08 00:00:00]} 2 114.88 -8.16 4 33.979 29.25 0.106 -0.011 {[2023-10-08 00:00:00]} 2 114.88 -8.16 6 33.978 29.251 0.105 -0.011 {[2023-10-08 00:00:00]} 2 114.88 -8.16 8 33.978 29.251 0.105 -0.011 {[2023-10-08 00:00:00]} 2 114.88 -8.16 10 NaN NaN NaN NaN {[2023-10-08 00:00:00]} 3 114.96 -8.16 0 33.995 29.171 0.109 -0.037 {[2023-10-08 00:00:00]} 3 114.96 -8.16 2 33.992 29.108 0.104 -0.03 {[2023-10-08 00:00:00]} 3 114.96 -8.16 4 33.992 29.11 0.102 -0.03 {[2023-10-08 00:00:00]} 3 114.96 -8.16 6 33.992 29.114 0.102 -0.03 {[2023-10-08 00:00:00]}
T1 = rmmissing(T1)
T1 = 15×9 table
Station Lon Lat Depth Salinity Temperature u v yyyy-mm-ddThh:mm:ss.sss _______ ______ _____ _____ ________ ___________ _____ ______ _______________________ 2 114.88 -8.16 0 33.981 29.324 0.11 -0.017 {[2023-10-08 00:00:00]} 2 114.88 -8.16 2 33.979 29.248 0.106 -0.011 {[2023-10-08 00:00:00]} 2 114.88 -8.16 4 33.979 29.25 0.106 -0.011 {[2023-10-08 00:00:00]} 2 114.88 -8.16 6 33.978 29.251 0.105 -0.011 {[2023-10-08 00:00:00]} 2 114.88 -8.16 8 33.978 29.251 0.105 -0.011 {[2023-10-08 00:00:00]} 3 114.96 -8.16 0 33.995 29.171 0.109 -0.037 {[2023-10-08 00:00:00]} 3 114.96 -8.16 2 33.992 29.108 0.104 -0.03 {[2023-10-08 00:00:00]} 3 114.96 -8.16 4 33.992 29.11 0.102 -0.03 {[2023-10-08 00:00:00]} 3 114.96 -8.16 6 33.992 29.114 0.102 -0.03 {[2023-10-08 00:00:00]} 4 115.04 -8.16 0 33.992 29.273 0.048 0.005 {[2023-10-08 00:00:00]} 4 115.04 -8.16 2 33.988 29.264 0.05 0.009 {[2023-10-08 00:00:00]} 4 115.04 -8.16 4 33.988 29.266 0.052 0.009 {[2023-10-08 00:00:00]} 4 115.04 -8.16 6 33.988 29.267 0.052 0.009 {[2023-10-08 00:00:00]} 4 115.04 -8.16 8 33.988 29.267 0.052 0.009 {[2023-10-08 00:00:00]} 4 115.04 -8.16 10 33.987 29.259 0.048 0.01 {[2023-10-08 00:00:00]}
Stations = accumarray(T1{:,1}, (1:size(T1,1)).', [], @(x){T1(x,:)})
Stations = 4×1 cell array
{0×0 double} {5×9 table } {4×9 table } {6×9 table }
[sz,ix] = sort(cellfun(@(x)size(x,1), Stations));
valid = [sz(sz~=0) ix(sz~=0)]
valid = 3×2
4 3 5 2 6 4
Stations_Sorted = cat(1,Stations{valid(:,2)}) % Reordered
Stations_Sorted = 15×9 table
Station Lon Lat Depth Salinity Temperature u v yyyy-mm-ddThh:mm:ss.sss _______ ______ _____ _____ ________ ___________ _____ ______ _______________________ 3 114.96 -8.16 0 33.995 29.171 0.109 -0.037 {[2023-10-08 00:00:00]} 3 114.96 -8.16 2 33.992 29.108 0.104 -0.03 {[2023-10-08 00:00:00]} 3 114.96 -8.16 4 33.992 29.11 0.102 -0.03 {[2023-10-08 00:00:00]} 3 114.96 -8.16 6 33.992 29.114 0.102 -0.03 {[2023-10-08 00:00:00]} 2 114.88 -8.16 0 33.981 29.324 0.11 -0.017 {[2023-10-08 00:00:00]} 2 114.88 -8.16 2 33.979 29.248 0.106 -0.011 {[2023-10-08 00:00:00]} 2 114.88 -8.16 4 33.979 29.25 0.106 -0.011 {[2023-10-08 00:00:00]} 2 114.88 -8.16 6 33.978 29.251 0.105 -0.011 {[2023-10-08 00:00:00]} 2 114.88 -8.16 8 33.978 29.251 0.105 -0.011 {[2023-10-08 00:00:00]} 4 115.04 -8.16 0 33.992 29.273 0.048 0.005 {[2023-10-08 00:00:00]} 4 115.04 -8.16 2 33.988 29.264 0.05 0.009 {[2023-10-08 00:00:00]} 4 115.04 -8.16 4 33.988 29.266 0.052 0.009 {[2023-10-08 00:00:00]} 4 115.04 -8.16 6 33.988 29.267 0.052 0.009 {[2023-10-08 00:00:00]} 4 115.04 -8.16 8 33.988 29.267 0.052 0.009 {[2023-10-08 00:00:00]} 4 115.04 -8.16 10 33.987 29.259 0.048 0.01 {[2023-10-08 00:00:00]}
.
  10 Kommentare
Adi Purwandana
Adi Purwandana am 15 Okt. 2023
Thank you @Star Strider for completing the solution!
Star Strider
Star Strider am 15 Okt. 2023
As always, my pleasure!

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