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Index error for the "ELS-Price choice code"

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형현
형현 am 26 Sep. 2023
Bearbeitet: Voss am 26 Sep. 2023
ns=10000;
face=10000;
val_date='2023-09-26';
mid_date= ['2024-03-21';'2024-09-23';'2025-03-21';'2025-09-23';'2026-03-23';'2026-09-18'];
strike=[1 0.95 0.9 0.85 0.8 0.75];
c_rate=[0.05 0.1 0.15 0.2 0.25 0.3];
dummy=0.1;
ki=0.5;
ki_YesNO='NO';
ref_S= [9179.5];
S=[6130];
r=0.05;
vol=[0.09];
rho=0.37;
temp_ch=datenum(mid_date)'-datenum(val_date);
mid_ch=temp_ch(find(temp_ch>=0));
c_rate=c_rate(find(temp_ch>=0));
strike=strike(find(temp_ch>=0));
N=mid_ch(end);
dt=1/365;
mid_size=length(mid_ch);
payment=zeros(ns,mid_size);
for i =1:ns
for j=1:mid_size
payment(i,j)=face*(1+c_rate(j));
end
end
corr=[1 rho;rho 1];
M=chol(corr);
SP1=zeros(ns,N+1);
SP1(:,1)=S(1);
for i=1:ns
w0=randn(N,2);
w=w0*M;
for j=2:N+1
SP1(i,j)=SP1(i,j-1)*exp((r-vol(1)^2/2)*dt+...
vol(1)*sqrt(dt)*w(j-1,1));
end
end
R1=SP1/ref_S(1);
WP=min(R1,[],2);
strike_ch=WP(:,mid_ch+1);
payoff=zeros(ns,mid_size);
for i=1:ns
for j=1:mid_size
if strike_ch(i,j)>=strike(j)
payoff(i,j)=payment(i,j);
break
end
end
continue
end
for i=1:ns
if payoff(i,:)==0
switch ki_YesNo
case 'NO'
ki_event=any(WP(i,:)<ki);
if ki_event==1
payoff(i,end)=face*WP(i,end);
else
payoff(i,end)=face*(1+dummy);
end
case 'Yes'
payoff(i,end)=face*WP(i,end);
otherwise
error('ki_YesNO = Yes or No');
end
end
end
exp_payoff=mean(payoff);
disc_payoff=zeros(1,mid_size);
for j=1:mid_size
disc_payoff(j)=exp_payoff(j)*exp(-r*mid_ch(j)/365);
end
ELS_Price=sum(disc_payoff)
--------------------------------------------------
If i run this code, there are "Index of location 2 exceeds array boundary. Index must not exceed 1." error occured, What should i do to solve this error code...

Antworten (1)

Angelo Yeo
Angelo Yeo am 26 Sep. 2023
In line 43, see that WP is an array of 10000 x 1. However, you are trying to extract elements by WP(:, mid_ch+1) where mid_ch is [177, 363, 542, 728, 909, 1088].
  2 Kommentare
형현
형현 am 26 Sep. 2023
I changed array of 10000x1 to 1x1089 vector. ___ Code change(WP=min(R1,[],2); → WP=min(R1);)
But i still have error code "Index of location 1 exceeds array boundary. Index must not exceed 1
Angelo Yeo
Angelo Yeo am 26 Sep. 2023
I would like to recommend debugging functionalities of MATLAB, and try to run the script line by line.
In your new code, see in line 47 that strike_ch is a 1x6 sized array, and you are accessing it by strike_ch(i, j). However, your iterator i changes its value from 1 to 10000.

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