Anonymous function of a series of nonlinear equations to accept vector input

I have a series of nonlinear equations, written as an anonymous function handle that outputs a vector solution of each function and Im trying to input a vector of x1,x2,x3. For the sake of the the error in my code I simplified it dramatically, however I cannot seem to get the function to output my desired results.

f= @(x1,x2,x3) [x1.^3;x2.^2;x3.^2]

f = function_handle with value:
    @(x1,x2,x3)[x1.^3;x2.^2;x3.^2]

x=[1;1;1]

x = 3×1

1 1 1

f(x')

Not enough input arguments.

Error in solution>@(x1,x2,x3)[x1.^3;x2.^2;x3.^2] (line 1)
f= @(x1,x2,x3) [x1.^3;x2.^2;x3.^2]

"Invalid expression. When calling a function or indexing a variable, use parentheses.

Otherwise, check for mismatched delimiters"

[Dyuman Joshi]

The function you have defined expects 3 inputs -

f= @(x1,x2,x3) [x1.^3;x2.^2;x3.^2]

f = function_handle with value:
    @(x1,x2,x3)[x1.^3;x2.^2;x3.^2]

But you have provided only 1 input, so it gives error

x=[1;1;1]

x = 3×1

1 1 1

f(x')

Not enough input arguments.

Error in solution>@(x1,x2,x3)[x1.^3;x2.^2;x3.^2] (line 1)
f= @(x1,x2,x3) [x1.^3;x2.^2;x3.^2]

I don't know how you about this error - "Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters"

Answer 1

[Star Strider]

Either:

f= @(x1,x2,x3) [x1.^3;x2.^2;x3.^2];

f = function_handle with value:
    @(x1,x2,x3)[x1.^3;x2.^2;x3.^2]

x=[1;1.2;1.3];

x = 3×1

1.0000 1.2000 1.3000

f(x(1),x(2),x(3))

ans = 3×1

1.0000 1.4400 1.6900

or:

f= @(x) [x(1).^3;x(2).^2;x(3).^2];

f = function_handle with value:
    @(x)[x(1).^3;x(2).^2;x(3).^2]

x=[1;1.2;1.3];

x = 3×1

1.0000 1.2000 1.3000

f(x')

ans = 3×1

1.0000 1.4400 1.6900

should work.

.

[Jordan Duffy]

Thank you, it worked! The latter is what I was looking for as I was hoping to avoid manually inputting into f, so that the solver is general for any nonlinear equation input function handle.

[Star Strider]

My pleasure!

If my Answer helped you solve your problem, please Accept it!

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