Creating 'n' matrices with each one with 'n' in its name
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Paul Barrette
am 17 Sep. 2023
Bearbeitet: Paul Barrette
am 20 Sep. 2023
I am building 'n' matrices line by line:
YEAR1 = zeros(DATE_RANGE(1,3));
YEAR2 = zeros(DATE_RANGE(2,3));
YEAR3 = zeros(DATE_RANGE(3,3));
...
To avoid manually entering each line, I would like to use a looping method, e.g.,
for n=1:10
YEARn = zeros(DATE_RANGE(n,3));
end
My searches bring me to the concept of 'dynamic access' (eval), which is not recommended. But am not sure if this applies to my case.
1 Kommentar
Stephen23
am 18 Sep. 2023
Bearbeitet: Stephen23
am 20 Sep. 2023
"To avoid manually entering each line, I would like to use a looping method"
That is a good approach. The best approach is to use arrays.
"My searches bring me to the concept of 'dynamic access' (eval)"
That is a very bad approach.
"But am not sure if this applies to my case."
That advice definitely applies to your case. Your approach using dynamic variable names is not recommended: your approach forces you into writing slow, complex, inefficient, obfuscated, buggy code that is hard to debug:
So far there is no obvious reason why you could not just use basic matrices or arrays for your data, just like MATLAB is designed for. If all of those arrays are the same size then a basic 3D array would suffice.
Note that calling ZEROS with one input argument often produces unexpected results.
Akzeptierte Antwort
Torsten
am 17 Sep. 2023
Verschoben: Torsten
am 17 Sep. 2023
YEAR{n} = zeros(DATE_RANGE(n,3));
2 Kommentare
Dyuman Joshi
am 17 Sep. 2023
That is, using Cell arrays to store matrices of different sizes.
@Paul Barrette, Using Cell arrays is also the first alternative mentioned in the thread you have linked -
Weitere Antworten (1)
Walter Roberson
am 17 Sep. 2023
See https://www.mathworks.com/matlabcentral/answers/2020976-i-want-to-store-the-vector-from-each-for-loop-iteration-how-can-i-do-this#answer_1310391 for sample code that iterates through variable names, a, b, c, d, e, ... z, aa, ab, ac, ...
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