scatteredInterpolant gives out NaN in some query points

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Philipp
Philipp am 9 Aug. 2023
Kommentiert: Philipp am 9 Aug. 2023
I have 3D-scattered testbench-data with x, y und z as setpoints and I want to make contourf-plots over x and y with z as adjustible parameter.
First i filtered and deleted doubled samples to make sure the datapoints are unique:
% Load Data
load('data.mat');
% Keep unique Data
setpoints = [data.x data.y data.z];
[setpointsu,idx] = unique(setpoints,'rows');
datau = data(idx,:);
Next I defined query-points which grid the room of the scattered data and interpolated:
xq = -50:5:0;
yq = 0:5:30;
zq = 25:5:75;
% Interpolieren
[Xq,Yq,Zq] = meshgrid(xq,yq,zq);
F.Value = scatteredInterpolant(x,y,z,datau.Value,'linear');
P.Value = F.Value(Xq,Yq,Zq);
But unfourtunately P.Value has some NaNs in the middle of the 'query room':
At these Points enough scattered input data should be availabe for interpolation.
What else could be causes for these red circled NaNs?
Thanks for your help.

Akzeptierte Antwort

Bruno Luong
Bruno Luong am 9 Aug. 2023
Bearbeitet: Bruno Luong am 9 Aug. 2023
Probably your data contains NaN at one or several points.
I don't quite understand your code
datau.Value
seems not valid since datau = data(idx,:); looks like an array.
Please share your data.
  6 Kommentare
Bruno Luong
Bruno Luong am 9 Aug. 2023
Bearbeitet: Bruno Luong am 9 Aug. 2023
Clearly you have point outside the convexhull AND you have NaN in your data (double check is not enough, quadriple check may be)
load('data.mat')
% Keep unique Data
x=data.x;
y=data.y;
z=data.z;
setpoints = [data.x data.y data.z];
[setpointsu,idx] = unique(setpoints,'rows');
datau = data(idx,:);
xq = -50:5:0;
yq = 0:5:30;
zq = 25:5:75;
% Interpolieren
[Xq,Yq,Zq] = meshgrid(xq,yq,zq);
find(isnan(datau.Value))
ans = 12×1
111 112 113 114 115 116 117 118 119 120
F.Value = scatteredInterpolant(x,y,z,datau.Value,'linear');
P.Value = F.Value(Xq,Yq,Zq);
xq = -50:5:0;
yq = 0:5:30;
zq = 25:5:75;
% Interpolieren
[Xq,Yq,Zq] = meshgrid(xq,yq,zq);
F.Value = scatteredInterpolant(x,y,z,datau.Value,'linear','nearest');
P.Value = F.Value(Xq,Yq,Zq);
P.Value(:,:,4)
ans = 7×11
0.4071 NaN NaN NaN 0.3632 0.4854 0.5979 0.5267 0.4373 0.3391 0.2409 NaN NaN NaN NaN 0.3955 0.4464 0.5515 0.5318 0.5121 0.4251 0.3269 NaN NaN NaN NaN 0.4262 0.4805 0.5317 0.4999 0.4682 0.4420 0.4172 NaN NaN NaN NaN 0.4182 0.3835 0.3556 0.4224 0.4003 0.3738 0.4393 0.5506 0.5072 0.4636 0.4433 0.4093 0.3093 0.1971 0.2639 0.3299 0.3920 0.4541 0.5508 0.5441 0.5064 0.4423 0.3797 0.3150 0.3080 0.2979 0.3229 0.3496 0.4106 0.5508 0.5463 0.5372 0.4609 0.3854 0.3785 0.4076 0.3975 0.3875 0.3774 0.3677
T=delaunayTriangulation(x,y,z);
F = convexHull(T);
close all
trisurf(F,x,y,z)
axis equal
hold on
plot3(Xq(:),Yq(:),Zq(:),'.')
Philipp
Philipp am 9 Aug. 2023
Your are right. Apologies. I checked the wrong column in my raw file.

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Weitere Antworten (1)

Walter Roberson
Walter Roberson am 9 Aug. 2023
By default, scatteredInterpolant with 'linear' method does not do extrapolation. If you attempt to query at a location that is outside the outside boundary of the triangulation of the reference points, then it would need extrapolation but that is not enabled by default for 'linear'
  1 Kommentar
Philipp
Philipp am 9 Aug. 2023
Thank you for your answer.
If I define ExtrapolationMethod as 'linear' there is no change in the outcome.
F.Value = scatteredInterpolant(x,y,z,datau.Value,'linear','linear');
The black x markers are showing the scattered input data points.

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