abs cannot be used in problem-based optimization expression

Can someone tell me why I cannot use abs() in this simple setup.
prob = optimproblem();
x = optimvar('x',1,1);
y = 1;
x0 = struct('x',0);
prob.Objective = abs(x-y); % sum(abs(x-y)) also doesn't work
Incorrect number or types of inputs or outputs for function 'abs'.
%prob.Objective = norm(x-y,1); % this however works
sol = solve(prob,x0)
If I use prob.Objective = norm(x-y,1) it wokks just fine

 Akzeptierte Antwort

Bruno Luong
Bruno Luong am 29 Jul. 2023

0 Stimmen

2 Kommentare

sqrt((x-y).^2) doesn't seem to work, either.
Syntaxically it works, but I have to add a small margin to avoid singularity of the derivative at 0
prob = optimproblem();
x = optimvar('x',1,1);
y = 1;
x0 = struct('x',0);
prob.Objective = sqrt((x-y).^2+eps); % sum(abs(x-y)) also doesn't work
sol = solve(prob,x0)
Solving problem using fminunc. Local minimum found. Optimization completed because the size of the gradient is less than the value of the optimality tolerance.
sol = struct with fields:
x: 1

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Produkte

Version

R2023a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by