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How to Convert a 3D Matrix into Cell Array of Desire Dimension

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Muhammad
Muhammad am 27 Jun. 2023
Kommentiert: Paul am 27 Jun. 2023
I have a matrix of N x M x Z 3D matrix. Where N x M is 2 x 100 and Z is 500. I want to convert it into cell array of Z x 1 ( 500 x 1) where each cell element will be N x M (2 x 100). How I can do this?

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Paul
Paul am 27 Jun. 2023
A = rand(2,100,500); % example data
C = squeeze(num2cell(A,[1 2])); % create cell array
whos C
Name Size Bytes Class Attributes C 500x1 852000 cell
isequal(cat(3,C{:}),A) % verify
ans = logical
1
  2 Kommentare
Muhammad
Muhammad am 27 Jun. 2023
@Paul what if I have 500 x 2 x 100 matrix to 500x1 cell array of 2x100 in each cell?
Paul
Paul am 27 Jun. 2023
A = rand(500,2,100);
C = num2cell(A,[2 3]); % line 1
At this point, each elment of C is 1 x 2 x 100 and is isequal to the corresponding slice of A. For example
size(C{293})
ans = 1×3
1 2 100
isequal(C{293},A(293,:,:))
ans = logical
1
To make each cell 2 x 100
C = cellfun(@(c) squeeze(c),C,'UniformOutput',false); % line 2
size(C)
ans = 1×2
500 1
size(C{293})
ans = 1×2
2 100
isequal(C{293},squeeze(A(293,:,:)))
ans = logical
1
Lines 1 and 2 can be combined into a single line if desired.
There may be a better way to do this.

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